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On Group and Semigroup Algebras
Paula Murgel Veloso
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1
‘Would you tell me, please, which way I ought to go from here?’
‘That depends a good deal on where you want to get to,’ said
the Cat.
‘I don’t much care where–’ said Alice.
‘Then it doesn’t matter which way you go,’ said the Cat.
‘–so long as I get somewhere,’ Alice added as an explanation.
‘Oh, you’re sure to do that,’ said the Cat, ‘if you only walk
long enough.’
(Lewis Carroll, Alice’s Adventures in Wonderland)
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Agradecimentos
Ao Prof. Arnaldo Garcia, do IMPA, pela orienta¸ao do meu mestrado e
do meu doutorado, e pelo incentivo.
Ao Prof. Guilherme Leal, da UFRJ, pela co-orienta¸ao do meu doutorado,
por ter-me proposto o problema que resultou no segundo cap´ıtulo desta tese,
e pelo apoio constante.
Aos Profs. Eduardo Esteves, do IMPA, Jairo Gon¸calves, da USP, Pavel
Zalesski, a UNB, e Amilcar Pacheco, da UFRJ, membros da banca de defesa
de tese, pelos coment´arios e sugest˜oes.
To Prof. Eric Jespers, from Vrije Universiteit B russel, for having proposed
the problem presented in the third chapter of this thesis, for the elucidative
conversations, good advice and kind hospitality during my stay in Brussels.
`
A Prof. Luciane Quo os, da UFRJ, pelas discuss˜oes matem´aticas sempre
esclarecedoras e bem-humoradas, e pela colabora¸ao no artigo no qual se
baseia o segunto cap´ıtulo desta tese.
To Dr. Ann Dooms, from Vrije Universiteit Brussel, for the nice and
fruitful discussions and friendly support, and for the collaboration on the
article in which the third chapter of this thesis is based.
Aos Profs. Paulo Henrique Viana (in memoriam), Carlos Tomei e Pe.
Paul Schweitzer, da PUC-Rio, por me mostrarem a beleza da Matem´atica e
pela amizade.
Aos professores do IMPA, em especial aos Profs. Karl-Otto St¨ohr, esar
Camacho, Paulo Sad e Manfredo do Carmo.
A todos os meus colegas do IMPA, principalmente aos meus amigos
de turma do mestrado e aos amigos da
´
Algebra Juscelino B ezerra, Cleber
Haubrichs, Juliana Coelho e Andr´e Contiero.
Aos professores e alunos grupo de
´
Algebra ao-Comutativa da UFRJ.
To the colleagues, professors and friends from Vrije Universiteit Brussel,
especially Isabel Goffa, Julia Dony and Kris Janssen.
A todos os funcion´arios do IMPA, em especial `aqueles da Comiss˜ao de
Ensino, da xerox e da seguran¸ca.
Ao CNPq, pelo apoio financeiro e pela oportunidade de passar um ano
i
ii
na Vrije Universiteit Brussel, Bruxelas, B´elgica, no programa de doutorado-
sandu´ıche.
Aos amigos Leandro Pimentel, Lourena Rocha, Marcos Petr´ucio Caval-
cante, Cec´ılia Salgado, Jos´e Cal Neto, Ricardo Bello, Taissa Abdalla, Kak´a
Boa Morte, Yolande Lisb ona, Wanderley Pereira, Alexandre Toledo, Helder
Gatti, Raul Tanaka, Eri Lou Nogueira, Paula Avellar, ergio Leiros, Karla
Suite, Cristina Diaconu, Maria Agustina Cibran, pela amizade, pela com-
panhia em todos os momentos, por enriquecerem e iluminarem minha vida.
`
A minha fam´ılia, principalmente aos meus pais Paulo Augusto e Sheila
Regina, e `a minha irm˜a Fl´avia, pelo ambiente familiar sempre alegre e aco-
lhedor, pelos constantes carinho, incentivo, paciˆencia e exemplo.
Paula Murgel Veloso
Julho, 2006
Contents
Agradecimentos i
Introduction iv
1 Preliminaries 1
1.1 Group Ring Theory . . . . . . . . . . . . . . . . . . . . . . . . 1
1.1.1 Basic Definitions . . . . . . . . . . . . . . . . . . . . . 1
1.1.2 Some Results . . . . . . . . . . . . . . . . . . . . . . . 10
1.2 Semigroup Ring Theory . . . . . . . . . . . . . . . . . . . . . 14
1.2.1 Prerequisite: Semigroup Theory . . . . . . . . . . . . . 14
1.2.2 Basic Definitions and Some Important Results . . . . . 21
2 Central Idempotents of Group Algebras of Finite Nilpotent
Groups 25
2.1 Primitive Idempotents of Semisimple Group Algebras of a Fi-
nite Abelian Group . . . . . . . . . . . . . . . . . . . . . . . . 26
2.2 Primitive Central Idempotents of Complex Group Algebras of
a Finite Nilpotent Group . . . . . . . . . . . . . . . . . . . . . 31
2.3 Some Questions for Further Investigation . . . . . . . . . . . . 38
3 The Normalizer of a Finite Semigroup and Free Groups in
the Unit Group of an Integral Semigroup Ring 40
3.1 The Normalizer of a Semigroup . . . . . . . . . . . . . . . . . 41
3.1.1 Characterization of N(±S) and Some Results . . . . . 44
3.1.2 The Normalizer Problem for Semigroup Rings . . . . . 53
3.2 Free Groups generated by Bicyclic Units . . . . . . . . . . . . 54
3.3 Some Questions for Further Investigation . . . . . . . . . . . . 55
Bibliography 57
Index 60
iii
Introduction
In this work, we are interested in Group Ring Theory. Although some
issues in Semigroup Ring Theory are also presented, the main focus is group
rings.
In Chapter 1, the basic theoretical foundations in group and semigroup
rings are laid. These ideas will be used throughout the entire work.
We begin with a presentation of definitions and theorems from Ring The-
ory, establishing their particular instances in the context of group rings. We
define group rings; the augmentation mapping; involutions; the Jacobson
radical of a ring; idempotents; simple comp onents; the character table of a
group; trivial, bicyclic and unitary units; the upper central series, the FC
center and the hypercenter of a group. Important results from Ring and
Group Ring Theory are then recalled, such as Wedderburn-Malcev theorem,
the decomposition of a semisimple ring in a direct sum of ideals, Wedderburn-
Artin theorem, Maschke theorem. For the sake of completeness and because
this may be elucidating in the sequel, some results are presented with their
proofs (Perlis-Walker theorem, the character method for obtaining primitive
central idempotents in group algebras over complex fields, Berman-Higman
lemma and its corollaries).
As a prerequisite to the study of semigroup rings, we briefly present
fundamental concepts from Semigroup Theory. We define semigroups and
special kinds of semigroups (regular, inverse, completely 0-simple, Brandt);
idempotents; principal factors and principal series of a semigroup; provide
basic res ults concerning the structure of semigroups, and present elucidative
and useful examples, such as Rees matrix semigroups and Malcev nilpotent
semigroups. Fundamental notions from Semigroup Ring Theory are then
exposed: we define semigroup and contracted semigroup rings, followed by
some clarifying examples, and results concerning the structure of semisimple
semigroup algebras, with special attention given to semigroup algebras over
the rational field, matrix semigroup rings and Munn algebras.
The reader who is well acquainted with all these concepts can concentrate
on the notation introduced.
iv
v
Chapter 2 is part of a joint work ([33]) with Prof. Luciane Quoos,
from the Institute of Mathematics, UFRJ. The main result in this chapter is
an alternative procedure to compute the primitive central idempotents of a
group algebra of a finite nilpotent group over the complex field, not relying
on the character table of the group, following methods previously applied
by Jespers and Leal to the rational case. As a partial result, we present
a formula for the primitive idempotents of the group algebra of the finite
abelian group over any field, which permits to build all cyclic codes over a
given finite field.
At first, some notation is fixed, and we state and prove a theorem that
yields a formula for the primitive idempotents in a semisimple group algebra
of a finite abelian group over an algebraically closed field; though the result is
extremely useful and new, the proof is quite easy and short. Next, the same
result is extended to a semisimple group algebra of a finite abelian group
over an any field, using the known method of Galois descent.
Then some technical definitions and facts, which appear in the literature
specific to the study of primitive central idempotents, are stated. A few
recent results on the subject are recalled, as they play an auxiliary role
to our main result. Finally, a fully internal description of the primitive
central idempotents of a group algebra of a finite nilpotent group over the
complex field is presented. The class ical method for computing primitive
central idempotents in complex group algebras relies on the character table
of the group, whose construction has complexity growing exponentially with
the order of the group. Our tool depends only on a lattice of subgroups of the
given group, satisfying some intrinsic conditions. Though the complexity of
this new method is still unknown, it is a theoretic alternative to the classical
character method that might turn out to be simpler and faster to use.
The material in Cha pter 3 is based on a joint work ([9]) with Dr. Ann
Dooms, from the Department of Mathematics, Vrije Universiteit Brussel,
where I had the opportunity of spending one year of my Ph.D. under the
support of CNPq, Brasil. We define the new concept of the normalizer of a
semigroup in the unit group of its integral semigroup ring. Several known
results and properties on the normalizer of the trivial units in the unit group
of an integral group ring are shown to hold for the normalizer of a finite
inverse semigroup. This indicates that our concept of normalizer of a semi-
group be haves as desired, and might be suitable and helpful in investigations
on the isomorphism problem in semigroup rings and partial group rings, as
is analogously done with group rings. We also construct free groups in the
unit group of the integral semigroup ring of an inverse semigroup, using a
bicyclic unit and its image under an involution.
Introduction
vi
We start by giving the definition of the normalizer of a semigroup in
the unit group of its integral semigroup ring. This definition coincides with
the normalizer of the trivial units in the case of an integral group ring and
behaves very much like it in inverse semigroups. These semigroups have a
natural involution, and semigroup rings of inverse semigroups are a wide
and interesting class containing, for instance, matrix rings and partial group
rings. This natural involution allows us to extend Krempa’s characterization
of the normalizer in group rings to a very useful property of the normalizer
of a semigroup. We will describe the torsion part of the normalizer and
investigate the double normalizer. Just like in group rings, the normalizer
of a semigroup contains the finite conjugacy center of the unit group of
the integral semigroup ring and the second center. It remains open what
the normalizer is in case the semigroup ring is not semisimple; we give an
example that provides some clues of how the normalizer might behave in
this case. This new concept of normalizer might be useful to tackle the
isomorphism problem for semigroup rings and partial group rings, and this
is an interesting path to follow in further studies.
The normalizer problem is then posed for integral semigroup rings, and
solved for finite Malcev nilpotent semigroups having a semisimple rational
semigroup ring. Like with integral group rings, we get that the normalizer
of a finite semigroup is a finite extension of the c enter of the semigroup ring.
Borel and Harish-Chandra showed the existence of free groups contained
in the unit group of an integral semigroup ring. As an additional consequence
of the investigation of the natural involution in a B randt semigroup, we
investigate the problem of constructing free groups in the unit group of an
integral semigroup ring using a bicyclic unit and its involuted image, following
Marciniak and Sehgal.
These are, so far, my contributions to the investigation of group rings.
Introduction
Chapter 1
Preliminaries
In this beginning chapter, we shall collect most of the needed background
in group and semigroup ring theory. For a more comprehensive approach, we
refer the reader to [25], [36], [4] and [30]. Those familiar with all the required
concepts can concentrate on the notation.
1.1 Group Ring Theory
1.1.1 Basic Definitions
Definition 1.1.1. Let G be a (multiplicative) group, and R be a ring with
identity 1. The group ring RG is the ring of all formal sums α =
gG
α
g
g,
α
g
R, with finite support supp(α) = {g G; α
g
= 0}. We say that α
g
is
the coefficient of g in α. Two elements α and β in RG are equal if and only
if they have the s ame coeffic ients. The zero element in RG is the element
0 :=
gG
0g, and the identity in RG is the element 1 := 1e +
gG\{e}
0g
(with e the identity in G, which shall be denoted henceforth by 1). The
sum α + β is the element
gG
(α
g
+ β
g
)g. The product αβ is the element
gG
γ
g
g, where γ
g
=
x,yG
xy=g
α
x
β
y
, for each g G. If R is a commutative
ring, then RG is an R-algebra and is called a group algebra.
Definition 1.1.2. Let RG be a group ring. The augmentation mapping
of RG is the ring homomorphism ε : RG R,
g
α
g
g →
g
α
g
. Its
kernel, denoted by ∆(G), is the augmentation ideal of RG. We have that
∆(G) =
gG
α
g
(g 1); α
g
R
.
If N is a normal subgroup of G, then there exists a natural homomorphism
ε
N
: RG R(G/N),
g
α
g
g →
g
α
g
gN. The kernel of this mapping,
denoted by
R
(G, N), is the ideal of RG generated by {n 1; n N}.
1
1.1. Group Ring Theory 2
We recall the definition of a ring with involution.
Definition 1.1.3. Let A be a commutative ring and R be an A-algebra. An
involution on R is an A-module automorphism τ : R R such that, for all
x, y R
τ(xy) = τ (y)τ(x) and τ
2
(x) = x.
Let G be a group. If R is a ring with an involution τ, we can define an
involution on RG extending τ as
(
gG
α
g
g) :=
gG
τ(α
g
)g
1
.
For instance, we can define an involution on CG, known as the classical
involution as (
gG
α
g
g) :=
gG
α
g
g
1
, where α
g
denotes the complex
conjugate of α
g
.
Now we need some concepts and results from Ring Theory that are rele-
vant in s tudying group rings.
Definition 1.1.4. Let R be a ring. The Jacobson radical of R, denoted by
Jac(R) or J (R), is defined as the intersection of all maximal left ideals in R
if R = 0, or as (0) if R = 0.
Evidently, if R = 0, maximal ideals always exist by Zorn’s Lemma.
In the definition above, we used left ideals; we could similarly define the
right Jacobson radical of R. It turns out that both definitions coincide (see
[17, §4]), so the Jacobson radical of a ring is a two-sided ideal.
The Jacobson radical of a ring has many important prop e rties and shows
up in a number of theorems in Group and Semigroup Ring Theory. We shall
mention only the ones we need in this work.
Lemma 1.1.5. [25, Lemma 2.7.5] Let R be a ring. Then J (R/J (R)) = 0.
Definition 1.1.6. An element e in a ring R is said to be an idempotent
if e
2
= e. If e is an idempotent, e = 0 and e = 1, then e is a nontrivial
idempotent. Two distinct idempotents e and f in a ring R are said to be
orthogonal if ef = fe = 0. An idempotent e is said to be primitive if it cannot
be written as e = e
+ e

, with e
and e

nonzero orthogonal idempotents.
Definition 1.1.7. Let R be a ring, and M be a (left) R-module. M is called
a simple (or irreducible) (left) R-module if M is nonzero and M has no (left)
R-submodules other than (0) and M. A nonzero ring R is said to be a simple
ring if (0) and R are the only two-sided ideals of R.
Preliminaries
1.1. Group Ring Theory 3
Definition 1.1.8. Let R be a ring, and M be a (left) R-module. M is
called a semisimple (or completely reducible) (left) R-module if every (left) R-
submodule of M is a direct summand of M (i.e., for every (left) R-submodule
N of M, there is a (left) R-submodule N
such that M = N N
).
Evidently, an analogous definition makes sense for rings (an equivalent
definition of semisimplicity for an Artinian ring R is Jac(R) = 0 [25, Theorem
2.7.16]) . It is worth observing that the notions of left and right semisimplicity
are equivalent for rings (see, for instance, [17, Corollary 3.7]).
If R is a semisimple ring, then the inner structure of R determines all the
simple R-modules, up to isomorphism.
Lemma 1.1.9. [25, Lemma 2.5.13] Let R be a semisimple ring, L be a
minimal left ideal of R and M be a simple R-module. We have that LM = 0
if and only if L M as R-modules; in this case, LM = M.
Certain rings can be decomposed as a direct sum of ideals. Recall that
a field F is a perfect field if every algebraic extension of F is separable, or,
equivalently, char(F ) = 0 or char(F ) = p = 0 and F
p
= F .
Theorem 1.1.10 (Wedderburn–Malcev). [35, Theorem 2.5.37] Let R be
a finite dimensional algebra over a perfect field F . Then
R = S(R) J (R) (as a vector space over F ),
where J (R) is the Jacobson radical of R, and S(R) is a subalgebra of R
isomorphic to R/J (R).
In the Wedderburn–Malcev Theorem, notice that, since S(R) R/J (R),
we have that S(R) is a semisimple algebra by Lemma 1.1.5.
The decomposition of a ring as a direct sums of ideals has a very important
particular case when the ring is semisimple.
Theorem 1.1.11. [25, Theorem 2.5.11] Let R =
s
i=1
A
i
be a decomposition
of a semisimple ring R as a direct sum of minimal two-sided ideals. Then
there exists a uniquely determined family {e
1
, . . . , e
s
} such that:
1. e
i
is a nonzero central idempotent, for i = 1, . . . , s;
2. e
i
e
j
= δ
ij
e
i
, for i, j = 1, . . . , s, where δ
ij
is Kronecker’s delta (in par-
ticular, e
i
and e
j
are orthogonal for i = j);
3. 1 =
s
i=1
e
i
;
Preliminaries
1.1. Group Ring Theory 4
4. e
i
cannot be written as e
i
= e
i
+ e

i
, where e
i
and e

i
are both nonzero
central orthogonal idempotents, for 1 i s.
Conversely, if there exists a family of idempotents {e
1
, . . . , e
s
} satisfying the
above conditions, then A
i
:= Re
i
are minimal two-sided ideals and R =
s
i=1
A
i
. The elements {e
1
, . . . , e
s
} are called the primitive central idempo-
tents of R.
Definition 1.1.12. The unique two-sided ideals of a semisimple ring R are
called the simple components of R
The following characterization of semisimple rings will be very important
for us:
Theorem 1.1.13 (Wedderburn–Artin). [17, Theorem 3.5] A ring R is
semisimple if and only if it is a direct sum of matrix algebras over divi-
sion rings, i.e., R M
n
1
(D
1
) . . . M
n
s
(D
s
), where n
1
, . . . , n
s
are posi-
tive integers and D
1
, . . . , D
s
are division rings. The number s and the pairs
(n
1
, D
1
), . . . , (n
s
, D
s
) are uniquely determined (up to permutations).
Now we can proceed to translate these ring theoretical concepts into valu-
able information about group rings.
Theorem 1.1.14 (Maschke). [25, Corollary 3.4.8] Let K be field and G be
a finite group. The group algebra KG is semisimple if and only if char(K)
does not divide |G|.
The following special elements of a group ring play a major role both in
Group Ring Theory and in the present work in particular.
Definition 1.1.15. Let R be a ring with identity and let H be a finite
subset of a group G. Define the element
H of RG as
H :=
hH
h. If
H = a is a cyclic subgroup of G of finite order, we shall sometimes write a
instead of
a. If |H| is invertible in R, we may define the element
H of RG
as
H :=
1
|H|
hH
h. If {C
i
}
iI
is the set of conjugacy classes of G which
contain only a finite number of elements, then the elements
C
i
in RG are
called the class sums of G over R.
These constructions enable us to get, for instance, a basis for the center
of a group ring and idempotent elements.
Theorem 1.1.16. [25, Theorem 3.6.2] Let G be a group and R be a com-
mutative ring. The set {
C
i
}
iI
of all class sums of G over R is a basis of
Z(RG) over R.
Preliminaries
1.1. Group Ring Theory 5
Lemma 1.1.17. [25, Lemma 3.6.6] Let R be a ring with identity and let H
be a finite subgroup of a group G. If |H| is invertible in R, then
H is an
idempotent of RG. Moreover,
H is central if and only if H G.
Group Representation Theory is a very powerful means to obtain new
results in Algebra. It is also a useful tool to “realize” an abstract group as
a concrete one. Some knowledge of Group Representation Theory is vital to
the understanding of group rings.
Definition 1.1.18. Let G be a group, R a commutative ring and V a free
R-module of finite rank. A representation of G over R, with representation
space V is a group homomorphism T : G GL(V ), where GL(V ) denotes
the group of R-authomorphisms of V . The rank of V is called the degree
of T and denoted by deg(T ). Fixing an R-basis of V , we can define an
isomorphism between GL (V ) and GL
n
(R), with n = deg(T ), where GL
n
(R)
denotes the group of n × n invertible matrices with coefficients in R. We can
thus consider the induced group homomorphism T : G GL
n
(R), in which
case we talk about a matrix representation.
Two representations T : G GL(V ) and T
: G GL(W ) of G over R
are equivalent representations if there exists an isomorphism of R-modules
φ : V W such that T
(g) = φ T (g) φ
1
, for all g G. A representation
T : G GL (V ) is an irreducible representation if V = 0 and if V and 0 are
the only invariant subspaces of V under T .
There is a strong connection between group representations and modules,
in which group rings play a major role, as it may be seen in the following
proposition:
Proposition 1.1.19. [25, Propositions 4.2.1 and 4.2.2] Let G be a group
and R be a commutative ring with identity. There is a bijection between the
representations of G over R and the (left) RG-modules which are free of finite
rank over R:
given a representation T : G GL(V ) of G over R, associate to
it the (left) RG-module M constructed from V by keeping the same
additive structure and defining the product of v V by α RG as
αv :=
gG
α
g
T (g)(v);
if M is a (left) R G-module which is free of finite rank over R, define
the representation T : G GL(M) ; T (g) : m → gm.
Two representations of G over R are equivalent if and only if the corre-
sponding (left) RG-modules are isomorphic. Also, a representation is irre-
ducible if and only if the corresponding (left) RG-module is simple.
Preliminaries
1.1. Group Ring Theory 6
The case when a group is represented over a field is of particular inter-
est. Historically, this was the first case to be studied and, therefore, most
applications were developed in this context.
The notion of character is of fundamental importance in Group Represen-
tation Theory and in Group Theory. It also shows up in the study of group
rings; in particular, there is a well-known formula for computing idempo-
tents of complex group algebras of finite groups that completely relies on
characters.
Definition 1.1.20. Let T : G GL(V ) be a representation of a group G
over a field K, with representation space V . The character χ of G afforded
by T is the map χ : G K; g → tr(T (g)), where tr(T (g)) is the trace of the
matrix associated to T (g) with respect to any basis of V over K. If T is an
irreducible representation, then χ is called an irreducible character
Proposition 1.1.21. [25, Proposition 5.1.3] Let G be a finite group and K be
a field such that char(K) |G|. Consider χ
1
, . . . , χ
r
the characters afforded by
a complete set T
1
, . . . , T
r
of inequivalent irreducible representations of G over
K. Then the set of all characters of G over K is the set {χ =
r
i=1
n
i
χ
i
; n
i
Z, i = 1, . . . , r}.
Next, we give an example of a very special representation and the corre-
sponding character, which will be useful in the sequel.
Example 1.1.22 (Regular Representation and Regular Character).
Let G be a finite group of order n. Consider the representation T : G
GL(CG) that associates to each g G the linear map T
g
: x → gx. This
is called the regular representation of G over C. Denote by ρ the character
afforded by T , i.e., the regular character.
Regard T as the matrix representation obtained by taking the e lements
of G in some order as an R-basis of RG. It is clear that the image of each
g G is a pe rmutation matrix. Notice that if g = 1, then gx = x, so all the
elements on the diagonal of matrix T (g) are equal to zero. Hence,
ρ(g) =
0 , if g = 1
|G|, , if g = 1.
We know that
CG M
n
1
(C) . . . M
n
s
(C) (CG)e
1
. . . (CG)e
s
(Theorem 1.1.13 and Theorem 1.1.11), with {e
1
, . . . , e
s
} the primitive central
idempotents of CG, and that, for all i = 1, . . . , s, M
n
i
(C) (CG)e
i
Preliminaries
1.1. Group Ring Theory 7
L
i
1
. . . L
i
n
i
, where L
i
j
denotes the irreducible (left) CG-module consisting
of n
i
× n
i
matrices having complex elements on the j
th
column and zeros
elsewhere. Clearly, by Lemma 1.1.9, for all j = 1, . . . , n
i
, L
i
j
L
i
1
(as CG-
modules), which has dimension n
i
over C. So, CG n
1
L
1
1
. . . n
s
L
s
1
.
If T
i
denotes the irreducible representation of G over C corresponding to
L
i
1
and χ
i
denotes the character T
i
affords, then we have that T =
s
i=1
n
i
T
i
and ρ =
s
i=1
n
i
χ
i
. Since n
i
= deg(T
i
) = χ
i
(1) (because χ
i
(1) = tr (T
i
(1)) =
tr(I
n
i
), where I
n
i
is the n
i
× n
i
identity matrix), it follows that
ρ =
s
i=1
χ
i
(1)χ
i
(*).
In the isomorphism CG M
n
1
(C) . . . M
n
s
(C), each idempotent
e
i
corresponds to the element (0, . . . , 0, I
n
i
, 0, . . . , 0), with I
n
i
the identity
matrix in M
n
i
(C). It is clear that T
i
(e
i
) is the linear function defined in L
i
1
by multiplication by the identity element, i.e., it is the identity function on
the simple component M
n
i
(C). Since e
i
e
j
= δ
ij
e
i
, it follows that
T
i
(e
j
) =
0 , if i = j,
I
n
i
, if i = j;
and
χ
i
(e
j
) =
0 , if i = j,
tr(I
n
i
) = deg(T
i
) , if i = j.
Lemma 1.1.23. Let G be a group and χ be a character afforded by a rep-
resentation of G. Then χ is constant on each of the conjugacy classes of
G.
Thus, the following definition makes sense:
Definition 1.1.24. Let G be a group and C
1
, . . . , C
r
be its conjugacy classes.
Choose, for each i, an arbitrary x
i
C
i
. The matrix (χ
i
(x
j
)) is called the
character table of G.
The case of group characters over the complex field will be extremely
important for us. We would like to know the dimensions of the complex
character table of a group. Notice that we learn, from example 1.1.22, that
the number of irreducible characters of a group G is equal to s, the number
of simple components in the Wedderburn–Artin decomposition of CG. In
fact, more is known:
Preliminaries
1.1. Group Ring Theory 8
Proposition 1.1.25. [25, Proposition 3.6.3, Theorem 4.2.7] Let G be a fi-
nite group and K be an algebraically closed field such that char(K) |G|.
Then the number of simple components of KG is equal to the number of
conjugacy classes of G, which equals the number of irreducible nonequivalent
representations of G over K.
Remark 1.1.26. Actually, the above proposition is still true in a slightly
more general setting: whe n K is a splitting field for G (see [25, Definition
3.6.4]).
Let A be a ring (with identity). We recall that we denote by U(A) the
multiplicative group of units of A, i.e.,
U(A) := {x A; xy = yx = 1, for some y A}.
There are not many known methods for constructing units in group rings,
most of them being either elementary or very old. Therefore, describing units
in group rings is a very active and important field of research.
Definition 1.1.27. Let R be a ring with identity and G be a group. An
element in the group ring RG of the form rg, where r U(R) and g G, is
called a trivial unit of RG, its inverse being the element r
1
g
1
.
For instance, the trivial units in ZG are the ele ments of ±G. Generally
speaking, group rings do have nontrivial units, though these may be hard to
find.
Let A be a ring with zero divisors. Take x, y A \ {0} such that xy = 0.
Then, for an arbitrary t A, η := ytx is a square zero element. Thus, 1 + η
is a unit, with inverse 1 η. A very special and important case occurs when
A is an integral group ring.
Definition 1.1.28. Let G be a group. Consider a, b G, with a of finite
order, and define
u
a,b
:= 1 + (1 a)ba.
Since (1 a)a = 0, u
a,b
is a unit in ZG, called a bicyclic unit.
Notice that the definition of bicyclic units still makes sense for integral
semigroup rings (see Section 1.2).
Proposition 1.1.29. [25, Proposition 8.1.6] Let g, h be elements of a group
G, with o(g) < . Then, the bicyclic unit u
g,h
is trivial if and only if h
normalizes g and, in this case u
g,h
= 1.
Preliminaries
1.1. Group Ring Theory 9
Next, we define a type of unit that is related to the classical involution
on an integral group ring.
Definition 1.1.30. Let G be a group. An element u ZG is said to be a
unitary unit if uu
= u
u = 1, where is the c lassical involution on ZG (see
Definition 1.1.3).
Now we recall some definitions from Group Theory that will be helpful
when studying the unit group of group rings and semigroup rings (see [34]).
Definition 1.1.31. Let G be a group. Consider the upper central series of
G
{1} = Z
0
(G) Z
1
(G) Z
2
(G) . . . ,
defined inductively as Z
1
(G) := Z(G) and Z
n
(G), the n
th
center of G, is the
only subgroup of G such that
Z
n
(G)/Z
n1
(G) = Z(G/Z
n1
(G)).
Notice that u Z
n+1
(G) if and only if (u, g) Z
n
(G), for all g G, where
(u, g) := u
1
g
1
ug is the commutator of u and g.
The union
Z
(G) :=
i
Z
i
(G)
is called the hypercenter of G. If there exists m N such that Z
(G) =
Z
m
(G) and m is the smallest possible number with this property, then m is
called the central height of G.
Let N and H be subsets of G. The centralizer of H in N is defined by
C
N
(H) := {g N; gh = hg, h H}.
The finite conjugacy center of G (or FC center of G) Φ(G) is the set of
all elements of G that have a finite number of conjugates in G, i.e.,
Φ(G) := {g G; |C
g
| < ∞} = {g G; (G : C
G
(g)) < ∞},
where C
g
denotes the G-conjugacy class of g G. It is well known ([25,
Lemma 1.6.3]) that Φ(G) is a characteristic subgroup of G .
Let H be a subgroup of G and g, h G. We denote by H
g
the conjugate
of H by g, i.e .,
H
g
= gHg
1
,
and we denote by h
g
the conjugate of h by g, i.e.,
h
g
= ghg
1
.
Preliminaries
1.1. Group Ring Theory 10
1.1.2 Some Results
In this subsection, we recall some results that will be helpful in the sequel.
Although these are basic facts from Group Ring Theory, we include their
proofs for the sake of completeness.
The next theorem deals with the problem of finding the Wedderburn–
Artin decomposition (according to Theorem 1.1.13) of a semisimple group
algebra KG of a finite abelian group G.
Theorem 1.1.32. [32, Perlis–Walker] Let G be a finite abelian group of
order n, and K be a field such that char(K) n. Then
KG
d|n
a
d
K(ζ
d
),
where a
d
K(ζ
d
) denotes the direct sum of a
d
copies of K(ζ
d
), ζ
d
are primitive
roots of unity of order d and a
d
= n
d
/[K(ζ
d
) : K], with n
d
denoting the
number of elements of order d in G.
Proof. Let us first analyse the case w hen G = a; a
n
= 1 is a cyclic group of
order n.
Consider the map φ : K[X] KG; f → f(a). We have that φ is a ring
epimorphism with kernel (X
n
1); thus KG
K[X]
(X
n
1)
. Consider X
n
1 =
d|n
Φ
d
, the decomposition of X
n
1 in cyclotomic polynomialnomials Φ
d
in
K[X], i.e., Φ
d
=
j
(Xζ
j
), where ζ
j
runs over all the primitive roots of unity
of order d, for all d|n. For each d, let Φ
d
=
a
d
i=1
f
d
i
be the decomposition of
Φ
d
in irreducible polynomials in K[X]. So,
X
n
1 =
d|n
a
d
i=1
f
d
i
.
Since char(K) n, it follows that X
n
1 is a separable polynomial, i.e.,
all the f
d
i
’s are distinct irreducible polynomials. By the Chinese Remainder
Theorem, it follows that
KG
d|n
a
d
i=1
K[X]
(f
d
i
)
.
Now, for each d
i
, we have that
K[X]
(f
d
i
)
K(ζ
d
i
), with ζ
d
i
a root of f
d
i
. Thus,
KG
d|n
a
d
i=1
K(ζ
d
i
),
Preliminaries
1.1. Group Ring Theory 11
and ζ
d
i
are primitive roots of unity of orders d dividing n. So, for a fixed d,
we have that K(ζ
d
i
) = K(ζ
d
j
), for any i, j = 1, . . . , a
d
, and we may write
KG
d|n
a
d
K(ζ
d
),
with ζ
d
a primitive root of unity of order d. Also, deg(f
d
i
) = [K(ζ
d
) : K],
for all i = 1, . . . , a
d
, so, taking degrees in the decomposition of Φ
d
, we have
that φ(d) = a
d
[K(ζ
d
) : K], where φ denotes Euler’s totient function. It
is well known that, since G is a cyclic group of order n, for any divisor d
of n, the number n
d
of elements of order d in G is precisely φ(d). Hence,
a
d
= n
d
/[K(ζ
d
) : K].
Suppose now that G is a finite abelian noncyclic group. We proceed by
induction on the order of G. So assume the result holds for any abelian group
of order less than n.
Using the Structure Theorem of Finite Abelian Groups, we can write
G = G
1
× H, with H a cyclic group of order n
2
and |G
1
| = n
1
< n.
By the induction hypothesis, we can write KG
1
d
1
|n
1
a
d
1
K(ζ
d
1
), with
a
d
1
=
n
d
1
[K(ζ
d
1
):K]
and n
d
1
denoting the number of elements of order d
1
in G
1
.
Therefore,
KG K(G
1
× H) (KG
1
)H (
d
1
|n
1
a
d
1
K(ζ
d
1
))H
d
1
|n
1
a
d
1
(K(ζ
d
1
)H)
(because, for any ring R and any groups G and H, it holds that R(G ×
H) (RG)H, and, if R =
iI
R
i
, with {R
i
}
iI
a family of rings, then
RG
iI
R
i
G). Decomposing each direct summand, we get
KG
d
1
|n
1
d
2
|n
2
a
d
1
a
d
2
K(ζ
d
1
, ζ
d
2
),
with a
d
2
= n
d
2
/[K(ζ
d
1
, ζ
d
2
) : K(ζ
d
1
)] and n
d
2
denoting the number of elements
of order d
2
in H. Taking d := lcm(d
1
, d
2
), it follows that K(ζ
d
) = K(ζ
d
1
, ζ
d
2
).
Set a
d
:=
lcm(d
1
,d
2
)=d
a
d
1
a
d
2
and let us see that the result follows. In fact,
since [K(ζ
d
) : K] = [K(ζ
d
1
, ζ
d
2
) : K(ζ
d
1
)][K(ζ
d
1
) : K], we have that
a
d
[K(ζ
d
) : K] =
lcm(d
1
,d
2
)=d
a
d
1
a
d
2
[K(ζ
d
1
, ζ
d
2
) : K(ζ
d
1
)][K(ζ
d
1
) : K] =
lcm(d
1
,d
2
)=d
n
d
1
n
d
2
.
From G = G
1
× H, each element in g G may be written as g = g
1
h,
with g
1
G
1
and h H and, since G is abelian, o(g) = lcm(o(g
1
), o(h)).
Hence,
lcm(d
1
,d
2
)=d
n
d
1
n
d
2
= n
d
, the number of elements of order d in G,
and a
d
= n
d
/[K(ζ
d
) : K]. Therefore KG
d|n
a
d
K(ζ
d
)
Preliminaries
1.1. Group Ring Theory 12
If one knows the Wedderburn–Artin decomposition of a semisimple ring,
it is only natural to search for its primitive central idempotents (Theorem
1.1.11). In Chapter 2, we develop methods to find primitive central idempo-
tents of semisimple group algebras of finite abelian groups and of complex
group algebras of finite nilpotent groups. In the latter case, there already
exists a classical method to compute the primitive central idempotents that
relies on the group’s character table.
The character table of a group provides the primitive central idempotents
of its complex group algebra by means of the following formula.
Theorem 1.1.33. [25, Theorem 5.1.11] Let G be a finite group, and
χ
1
, . . . , χ
r
be all the irreducible complex characters of G. For i = 1, . . . , r,
define
e
i
:=
χ
i
(1)
|G|
gG
χ
i
(g
1
)g.
Then e
1
, . . . , e
r
are the primitive central idempotents of the complex group
algebra CG.
Proof. For each i = 1, . . . , r, we may write e
i
=
gG
α
g
g. Evaluating the
regular character ρ on e
i
, we get ρ(e
i
) =
gG
α
g
ρ(g) = α
1
|G|. Thus, for
any x G, we have that ρ(x
1
e
i
) =
gG
α
xg
ρ(g) = α
x
|G|. From Example
1.1.22, () it follows that α
x
|G| = ρ(x
1
e
i
) =
r
j=1
χ
j
(1)χ
j
(x
1
e
i
). Consider
T
i
the representation associated to the character χ
i
. We get that
T
i
(x
1
e
i
) = T
i
(x
1
)T
i
(e
i
) = T
i
(x
1
),
T
j
(x
1
e
i
) = T
j
(x
1
)T
j
(e
i
) = 0,
for i = j, and thus
χ
i
(x
1
e
i
) = χ
i
(x
1
),
χ
j
(x
1
e
i
) = 0,
for i = j. As a result,
α
x
=
1
|G|
χ
i
(1)χ
i
(x
1
),
for all x G. Hence, from e
i
=
gG
α
g
g, the desired formula follows.
Now we proceed to state some results about trivial units (see Definition
1.1.27) in integral group rings that will be very relevant in the study of the
normalizer of integral semigroup rings in Chapter 3.
The next result states that the trivial units are the only unitary units
(see Definition 1.1.30); it has an elementary proof and, nevertheless, is very
useful in the study of units in group rings.
Preliminaries
1.1. Group Ring Theory 13
Proposition 1.1.34. Let G be a group and γ =
gG
γ
g
g ZG. We have
that γγ
= 1 if and only if γ ±G.
Proof. If γ = ±g, for g G, then γ
= ±g
1
= γ
1
.
Conversely, if γγ
= 1, then we have that
1 =
gG
γ
2
g
1 +
g,hG
g=h
γ
g
γ
h
gh
1
.
Thus, 1 =
gG
γ
2
g
1 and 0 =
g,hG
g=h
γ
g
γ
h
gh
1
. Since γ
g
Z for all g G,
this implies that γ
g
0
= ±1 for a unique g
0
G and γ
g
= 0 for all g = g
0
.
Hence, γ = ±g
0
.
The next result, due to Berman and Higman, is also valid for infinite
groups; however, we shall only need it for finite groups, and, in this case,
there is an independent proof.
Lemma 1.1.35 (Berman–Higman). Let γ =
gG
γ
g
g be a unit of finite
order in the integral group ring ZG of a finite group G. If γ
1
= 0 then
γ = γ
1
= ±1.
Proof. Let n = |G| and suppose γ
m
= 1, for some positive integer m. Con-
sider the regular representation T and the regular character ρ (see Example
1.1.22) on the group algebra CG, and regard ZG as a subring of CG. We
have that
ρ(γ) =
gG
γ
g
ρ(g) = γ
1
n.
Since γ
m
= 1, we have that T (γ)
m
= T (γ
m
) = T (1) = I; thus T (γ) is a
root of the p olynomial X
m
1 = 0, which is separable. So there is a basis
of CG such that T (γ) is an n × n diagonal matrix, with m
th
roots of unity
ζ
i
in the diagonal and zeros elsewhere.
Hence,
ρ(γ) = tr(T (γ)) =
n
i=1
ζ
i
=
1
,
and, taking absolute values,
n|γ
1
|
n
i=1
|ζ
i
| = n.
Now, n|γ
1
| n, for γ
1
Z, then we must have |γ
1
| = 1 and also
n
i=1
|ζ
i
| =
|
n
i=1
ζ
i
|, which happens if and only if ζ
1
= . . . = ζ
n
.
Therefore,
1
=
1
, and consequently γ
1
= ζ
1
= ±1. So, T (γ) = ±I
and γ = ±1.
Preliminaries
1.2. Semigroup Ring Theory 14
The following corollaries of the Berman–Higman Lemma will be extremely
helpful for us.
Corollary 1.1.36. Let A be a finite abelian group. Then the group of torsion
units of the integral group ring ZA is the group of trivial units ±A.
Proof. Let γ =
gA
γ
g
g ZA be a unit of finite order. Suppose that
γ
g
0
= 0, for some g
0
A. Then, due to the commutativity of A, γg
1
0
is also
a unit of finite order in ZA and (γg
1
0
)
1
= γ
g
0
= 0. By Lemma 1.1.35, we
have that γg
1
0
= ±1, i.e., γ = ±g
0
.
Corollary 1.1.37. Let G be a finite group. Then the group of all torsion
central units of the integral group ring ZG is the group of the central trivial
units ±Z(G).
1.2 Semigroup Ring Theory
Before getting to the topic of semigroup rings itself, we will need some
theory about semigroups.
1.2.1 Prerequisite: Semigroup Theory
Some notions on Semigroup Theory are generalizations of concepts from
Group Theory; however, most of them resemble Ring Theory.
Definition 1.2.1. A semigroup is a nonempty set with an associative bi-
nary operation, which will be denoted multiplicatively by juxtaposition of
elements.
An element θ of a semigroup S is called a zero element if = θs = θ , for
all s S. A null semigroup is a semigroup with zero in which the product
of any two elements is the zero element.
An element 1 of a semigroup S is called an identity if s1 = 1s = s, for all
s S. A monoid is a semigroup that has an identity.
An element s in a monoid S is said to be an invertible element (or a unit)
if there exists s
S such that ss
= s
s = 1; the element s
is called the
inverse element of s and is denoted s
1
. The unit group of a monoid S is the
group U(S) := {s S; sr = rs = 1 , for some r S}. A grou p S is a monoid
in which every element is invertible, i.e., S = U(S). A group S is said to be
an abelian group (or a commutative group) if sr = rs, for all s, r S.
A semigroup homomorphism is a function f : S T from a semigroup
S to a semigroup T such that f (rs) = f(r)f(s), for all r, s S.
Preliminaries
1.2. Semigroup Ring Theory 15
If S is a semigroup, then we denote by S
1
the smallest monoid containing
S. So
S
1
=
S , if S already has an identity element;
S {1} , if S does not have an identity element,
with s1 = 1s = s, for all s S
1
. Similarly, we denote by S
0
the smallest
semigroup with a zero containing S. So
S
0
=
S , if S already has a zero element;
S {θ} , if S does not have a zero element,
with = θs = θ, for all s S
0
. In particular, for a group G, we say that
G
0
is a group with zero.
Adjoining a zero normally simplifies arguments, while adjoining an iden-
tity is often useless, as the structure theory of semigroups relies on s ubsemi-
groups and ideals, which do not have an identity in general.
The following example describes a kind of matrix semigroup that is of
utmost importance in the algebraic theory of semigroups.
Example 1.2.2 (Rees Matrix Semigroup). Let G be a group, G
0
=
G {θ} be the group with zero obtained from G by the adjunction of a zero
element θ (as in Definition 1.2.1), and I and M be arbitrary nonempty sets.
By an I × M matrix over G
0
we mean a mapping A : I × M G
0
, for which
we use the notation a
i,m
:= A(i, m), for (i, m) I × M, and (a
i,m
) := A.
By a Rees I × M matrix over G
0
we mean an I × M matrix over G
0
having at most one nonzero element. For g G, write (g)
i,m
, with i I
and m M, for the I × M matrix having g in the (i, m)-entry, its remaining
entries being θ. For any i I and m M, the expression (θ)
i,m
denotes the
I × M zero matrix, which will be also be denoted by θ.
Now let P be a fixed arbitrary M × I matrix over G
0
. We define a
multiplication operation in the set of all Rees I × M matrices over G
0
as
AB := A P B, where denotes the usual multiplication of matrices and,
in p erforming this, we agree that, for g G
0
, θ + g = g = g + θ. We call P
the sandwich matrix with respect to this multiplication. Clearly, the set of
all Rees I × M matrices over G
0
is closed under this operation, which is also
associative. So, we can consider the Rees I × M matrix semigroup over the
group with zero G
0
with sandwich matrix P and denote it by M
0
(G, I, M, P ).
When the sets I and M are finite, say |I| = n and |M| = m, we will write
M
0
(G, I, M, P ) simply as M
0
(G, n, m, P ).
In fact, this type of semigroups is very natural, for instance:
Preliminaries
1.2. Semigroup Ring Theory 16
1. In the ring of integral n × n matrices M
n
(Z), denote by e
i,j
the n × n-
matrix with 1 as the (i, j)-entry and zeros elsewhere. We call e
i,j
a
matrix unit . We may multiply matrix units in the following way:
e
i,j
e
k,l
=
e
i,l
, if j = k,
0, if j = k.
The matrix units in M
n
(Z) and the n × n zero matrix form, with
this multiplication, the matrix semigroup M
0
({1}, n, n, I
n
), where I
n
denotes the n × n-identity matrix.
2. Let G be a group with identity 1 and P =
1
1
. The matrix semi-
group M
0
(G, 1, 2, P ) is isomorphic to the semigroup G
1
G
2
{θ},
with G
1
and G
2
isomorphic copies of G such that G
1
G
2
G
2
and
G
2
G
1
G
1
.
Now we define some special subsets of semigroups having a certain alge-
braic structure.
Definition 1.2.3. A subsemigroup of a semigroup is a nonempty subset
which is closed under multiplication. A submonoid of a semigroup is a sub-
semigroup with an identity. A subgroup of a semigroup is a subsemigroup
that is a group.
If T is a nonempty subset of a semigroup S, we write T for the sub-
semigroup generated by T (if T is finite, say T = {t
1
, . . . , t
n
}, we often write
t
1
, . . . , t
n
instead of T ). A semigroup S is said to be a cyclic semigroup
if S = x for some x S. An element x of a semigroup S is a periodic
element if x is finite. A semigroup is a periodic semigroup if every cyclic
subsemigroup is finite.
Note that the identity of a subgroup G of a semigroup S need not to be
the identity of S (actually, S may not have an identity at all). As as example,
consider S := M
0
(G, n, n, I
n
), where I
n
denotes the n × n identity matrix
and G is any group; S has no identity element. But M := {s = ge
1,1
M
0
(G, n, n, I
n
); g G} is a subgroup of S with identity 1e
1,1
.
Definition 1.2.4. An element e in a semigroup S is called an idempotent
if e = e
2
. We write E(S) for the set of idempotent elements of a semigroup
S. The set E(S) has a natural partial order: e f ef = fe = e.
An idempotent e in a semigroup S is said to be primitive if it is a nonzero
idempotent and if it is minimal with respect to the partial order in E(S).
Preliminaries
1.2. Semigroup Ring Theory 17
Notice that the notion of primitive idempotent in a ring (Definition 1.1.6)
is equivalent to the one given above.
Observe that a finite cyclic semigroup always contains an idempotent.
In fact, let s be a finite cyclic semigroup. So there exist positive integers
n and k so that s
n+k
= s
n
. Hence, s
n+vk
= s
n
, for any positive integer v.
In particular, s
n(1+k)
= s
n
. So the semigroup s contains an element a so
that a
m
= a, for some integer m 2. If m = 2, then a is an idempotent.
Otherwise, a
m1
, a
m2
s and
(a
m1
)
2
= a
m1
a
m1
= (a
m1
a)(a
m2
) = a
m
a
m2
= aa
m2
= a
m1
,
and then a
m1
is an idempotent.
Definition 1.2.5. Let I be a nonempty subset of a semigroup S. We say I
is a right ideal of S if xs I, for all s S and x I, i.e., IS
1
I. A left
ideal is defined analogously. We call I an ideal of S if it is a left and a right
ideal of S.
For a S, the ideal generated by a is defined as J
a
:= S
1
aS
1
= SaS
Sa aS {a}.
Definition 1.2.6. A semigroup S is said to be a regular semigroup if it
satisfies the Von Neumann regularity condition, i.e., for every s S, there
exists x S such that sxs = s. A semigroup is said to be an inverse
semigroup if it is regular and its idempotents commute; or, equivalently,
every principal right ideal and every principal left ideal of S has a unique
idempotent generator; or, also equivalently, if for every s S, there exists a
unique x S such that sx s = s and xsx = x ([4, Theorem 1.17]).
Let S be a semigroup. Define the the center of S as the subset Z(S) =
{x S; xs = sx, s S}.
If a semigroup S has a minimal ideal K, then K is called a kernel of S.
Clearly, any two distinct minimal ideals of S are disjoint. Since two ideals A
and B of S always contain their set product AB, it follows that S can have
at most one kernel K. Notice that S may not have a kernel at all (this is the
case, for instance, if S is an infinite cyclic semigroup). If S has a kernel K,
K may be characterized as the intersection of all ideals of S, because K is
contained in every ideal of S.
Let e be an idempotent in a semigroup S. Then eSe = {ese; s S} is
a submonoid of S with identity element e. Now, eSe coincides with {x
S; ex = xe = x}, the set of elements of S for which e is an identity. Consider
H
e
:= U(eSe), the unit group of the monoid eSe. Then H
e
is a subgroup
of S and it is the largest subgroup of S for which e is the identity. Such
subgroups are called the maximal subgroups of S. Notice that all the maximal
Preliminaries
1.2. Semigroup Ring Theory 18
subgroups of S are isomorphic. There is a one-to-one correspondence between
the idempotents e and maximal subgroups H
e
of a semigroup S, since e is
the unique idempotent element of H
e
. H
e
contains every subgroup of S that
meets H
e
. Thus, distinct maximal subgroups are disjoint.
Now, the Rees matrix semigroups defined in Example 1.2.2 are important
in characterizing some special kinds of semigroups.
Lemma 1.2.7. [4, Lemma 3.1] Let G be a group, I and M be arbitrary
nonempty sets, and P be a M × I matrix over G
0
. Then the Rees I ×
M matrix semigroup M
0
(G, I, M, P ) over G
0
with sandwich matrix P is a
regular semigroup if and only if each row and each column of P contains a
nonzero entry. In such a case, P is said to be a regular matrix.
Proposition 1.2.8. [30, Lemma 1.4] Let G be a group, I and M be arbitrary
nonempty sets, and P be a M × I matrix over G
0
. Then the nonzero idempo-
tents of the Rees I ×M matrix semigroup M
0
(G, I, M, P ) over G
0
with sand-
wich matrix P are precisely the elements e = (p
1
j,i
)
i,j
, with p
j,i
= θ. Define
S
i,j
:= {(g)
i,j
; g G
0
, p
j,i
= θ}. Then all the S
i,j
\ {θ} together with {θ} are
the maximal subgroups of M
0
(G, I, M, P ). In fact, eM
0
(G, I, M, P )e S
i,j
.
Notice that, on the proposition above, all the S
i,j
are isomorphic to G
0
.
Definition 1.2.9. Let S be a semigroup. An equivalence relation ρ on S is
called a right congruence relation if, for all a, b, c S, it holds that aρb implies
acρbc. An equivalence relation ρ on S is called a left congruence relation if,
for all a, b, c S, it holds that aρb implies caρcb. An equivalence relation
ρ on S is a congruence relation if it is both a right and a left congruence
relation. We denote by S/ρ the set of the equivalence classes and by a the
equivalence class containing the element a S. S/ρ becomes a semigroup
with multiplication defined as ab = ab. We call S/ρ the factor semigroup of
S modulo ρ.
Let S be a semigroup and I be an ideal in S. Define ρ the Rees congruence
modulo I on S as aρb a = b or a, b I. We write S/I for S/ρ and call
this the Rees factor semigroup of S modulo I. As a convention, the Rees
factor S/ is defined to be S (even though the empty set is not an ideal).
Clearly, for a semigroup S and a congruence relation ρ, there is a natural
semigroup homomorphism S S/ρ; a → a. Congruence relations on groups
yield the concept of normal subgroups.
Let S be a semigroup and I be an ideal in S. Notice that the equivalence
classes of S/I are I itself and every one-element set {a}, with a S \ I.
Thus, as a set, S/I may be identified with S \ I with an element θ adjoined,
Preliminaries
1.2. Semigroup Ring Theory 19
and such that = θa = θ, so θ is actually a zero element. Intuitively,
when we pass from S to S/I, we identify all the elements of I with θ and
the nonzero elements of S/I correspond with S \ I; therefore, we will usually
denote the nonzero elements of S/I as a (with a S \ I) instead of a. There
is a one-to-one correspondence between the ideals of S containing I and the
ideals of S/I.
In analogy with what happens in groups and rings, we have the following
lemma:
Lemma 1.2.10. Let S be a semigroup and I, J be ideals of S such that
I J. Then J/I is an ideal of S/I and (S/I)/(J/I) S/J.
We introduce, in analogy to simple rings, special kinds of semigroups that
are “indecomposable” in some sense.
Definition 1.2.11. A semigroup is called a simple semigroup if it has no
ideals other than itself.
A semigroup S with a zero θ is said to be a 0-simple semigroup if S has
no ideals other than S and {θ}, and S
2
= S, or, equivalently S has no proper
ideals other than {θ}, and S is not a null semigroup of cardinality two.
A semigroup is called a completely 0-simple semigroup if it is 0-simple
and it contains a primitive idempotent (see Definition 1.2.4).
A semigroup is said to be a Brandt semigroup if it is a completely 0-simple
inverse semigroup.
Notice that if S is a semigroup having zero element θ, then {θ} is always
an ideal of S. Thus, the definition of simple semigroup is not very interesting.
Completely 0-simple semigroups, on the other hand, will turn out to be the
building blocks of the structure theory of semigroups.
Let us characterize 0-simple semigroups and completely 0-simple semi-
groups in more detail:
Lemma 1.2.12. [4, Lemma 2.28] Let S be a semigroup with zero θ, and
such that S = θ. Then S is 0-simple if and only if SaS = S for every a S,
a = θ.
Lemma 1.2.13. ([4, §2.7, Exercise 11] A semigroup S with zero is com-
pletely 0-simple if and only if all of the following conditions are satisfied:
1. S is regular;
2. every nonzero idempotent of S is primitive;
3. if e and f are nonzero idempotents of S, then eSf = θ.
Preliminaries
1.2. Semigroup Ring Theory 20
The next theorem characterizes completely 0-simple semigroups and also
Brandt semigroups.
Theorem 1.2.14. [4, Theorem 3.5, Theorem 3.9] A semigroup is completely
0-simple if and only if it is isomorphic to a regular Rees matrix semigroup
over a group with zero.
Furthermore, a semigroup is a Brandt semigroup if and only if it is iso-
morphic to a Rees matrix semigroup M
0
(G, M, M, I
|M|
) over a group with
zero G
0
with the M × M identity matrix I
|M|
as sandwich matrix.
Definition 1.2.15. Let S be a semigroup with zero. Define the equivalence
relation J in S by xJ y J
x
= J
y
(see Definition 1.2.5), i.e., x and y
generate the same ideal in S. We use the notation J(x) for the J -class of
S containing x, i.e., J(x) is the set of elements that generate the ideal J
x
.
Two elements are said to be J -equivalent if they determine the same J -
class. Let I
x
denote the set of elements of J
x
that do not generate J
x
, i.e.,
I
x
:= {y J
x
; J
y
J
x
}. So I
x
is an ideal of S and J
x
\ I
x
= J(x). The
quotient S
x
:= J
x
/I
x
is called a principal factor of S
By a principal series of S we mean a strictly decreasing chain of ideals S
i
of S, begining with S and ending with {θ}, and such that there is no ideal of
S strictly between S
i
and S
i+1
, for i = 1, . . . , m. The factors of a principal
series of S are the Rees factors S
i
/S
i+1
.
Remark 1.2.16. Notice that the definition of principal series with which we
are working is slightly different from that of [4]. Our series ends with the
zero ideal rather than the empty set; so we will always adjoin a zero to the
semigroup before considering its principal series.
From the following lemma, it becomes clear why 0-simple and completely
0-simple semigroups are said to be “building blocks” for all semigroups.
Lemma 1.2.17. [4, Lemma 2.39] Each principal factor of any semigroup
(with zero) is either 0-simple or null.
Theorem 1.2.18. [4, Theorem 2.40] Let S be a semigroup (with zero), hav-
ing principal series S = S
1
S
2
· · · S
m
S
m+1
= {θ}. Then its factors
are isomorphic in some order to the principal factors of S. In particular, any
two principal series of S have isomorphic factors.
Corollary 1.2.19. [4, Corollary 2.56] Any periodic (in particular, any finite)
0-simple semigroup is completely 0-simple.
Theorem 1.2.20. Every finite semigroup with zero has a principal series
and the principal factors are either completely 0-simple or null semigroups.
Preliminaries
1.2. Semigroup Ring Theory 21
To end this section, we give an example of a well known class of semi-
groups.
Example 1.2.21 (Malcev Nilpotent Semigroups). [21, 26, 30] Let S
be a semigroup. Consider, for x, y in S, and w
1
, w
2
, . . . , w
i
, . . . S
1
, the
following sequence defined inductively:
x
0
= x,
y
0
= y,
and for n 0
x
n+1
= x
n
w
n+1
y
n
,
y
n+1
= y
n
w
n+1
x
n
.
If x
n
= y
n
, for all x
0
, y
0
S and all w
i
in S
1
, and n is the least positive
integer with this property, then S is said to be a Malcev nilpotent semigroup
of class n.
Finite Malcev nilpotent semigroups have been classified by Okni´nski in
[31]. It is interesting to observe that a group is Malcev nilpotent of class n if
and only if it is nilpotent of class n in the classical sense [30, Theorem 7.2].
We have that a Brandt semigroup which is a matrix semigroup over a
nilpotent group (Theorem 1.2.14) is Malcev nilpotent. Actually, these are
the only Malcev nilpotent completely 0-simple semigroups [16, Lemma 2.1].
Hence, the completely 0-simple principal factors of a finite Malcev nilpotent
semigroup are Brandt semigroups, which are of the form M
0
(G, M, M, I
|M|
),
where I
|M|
denotes the M × M -identity matrix and G is a nilpotent group.
1.2.2 Basic Definitions and Some Important Results
Semigroup rings arise naturally as a generalization of group rings w hen
we replace the group by a semigroup.
Definition 1.2.22. Let S be a semigroup, and R be a ring with identity
1. The semigroup ring RS is the ring of all formal sums α =
sS
α
s
s,
α
s
R, with finite support supp(α) = {s S; α
s
= 0}. We say that α
s
is the
coefficient of s in α. Two elements α and β in RS are equal if and only if they
have the same coefficients. The sum α + β is the element
sS
(α
s
+ β
s
)s.
The product αβ is the element
sS
γ
s
s, where γ
s
=
x,yS
xy=s
α
x
β
y
, for each
s S. If R is a commutative ring, then RS is an R-algebra and is called a
semigroup algebra.
Preliminaries
1.2. Semigroup Ring Theory 22
Let S be a semigroup without zero element, and R be a ring. Notice that
RS
0
RS × . In order to “get rid of the factor , we will need the
notion of contracted semigroup ring.
Definition 1.2.23. Let S be a semigroup with a zero element θ, and R be a
ring with identity 1. The contracted semigroup ring R
0
S of S over R is the
ring RS/Rθ, i.e., the elements of R
0
S may be identified with the set of finite
sums α =
sS
α
s
s, α
s
R, s S \ {θ}, with componentwise addition and
multiplication defined on the R-basis S \ {θ} as
st =
st, if st = θ,
0, if st = θ,
and then extended by distributivity to all e lements. If S is a semigroup
without zero element, we define the contracted semigroup ring of S over R
as R
0
S := RS.
Some natural classes of rings may be treated as contracted semigroup
rings and not as (not contracted) semigroup rings.
Example 1.2.24. 1. Let R be a ring, n > 1 be an integer, and let S be
the s emigroup of n × n matrix units with zero (as in Example 1.2.2.1).
Then R
0
S M
n
(R). Notice that, if K is a field, then M
n
(K) is a
simple ring. But a (not contracted) semigroup algebra of a nontrivial
semigroup is never simple, as it contains the augmentation ideal, that
is, the ideal of all elements of the semigroup algebra of which the sum
of the coefficients is zero.
2. Let R be a ring, I and M be nonempty sets and P = (p
m,i
) be an
M × I matrix over R. Consider the set M(R, I, M, P ) of all I × M
matrices over R with finitely many nonzero entries. For any A = (a
i,m
)
and B = (b
i,m
) M(R, I, M, P ), addition is defined entrywise and
multiplication is defined as follows:
AB := A P B, with denoting the usual matrix multiplication.
With these operations M(R, I, M, P ) becomes a ring, called a ring of
matrix type over R with sandwich matrix P . If each row and column of
P contains an invertible element of R, then we call M(R, I, M, P )
a Munn ring. Note that if i I, m M and p
m,i
is a unit of
R then e := (p
1
m,i
)
im
is an idempotent of M(R, I, M, P ) such that
eM(R, I, M, P )e R. When the sets I and M are finite, say |I| = n
and |M| = m, we will denote M(R, I, M, P ) simply as M(R, n, m, P ).
Preliminaries
1.2. Semigroup Ring Theory 23
Let G be a group. It is easily verified that R
0
M
0
(G
0
, I, M, P )
M(RG, I, M, P ) (see Example 1.2.2). If R = ZG, m = n and P is
the n × n identity matrix, then M(R, n, m, P ) = M
n
(ZG).
3. Let K be a field, be any nonempty set, X be the free monoid on
an alphabet {x
i
; i }, and I be an ideal in KX generated by an
ideal J of X. We call KX/I a monomial algebra. We have that KX/I
is a K-space with basis the Rees f actor semigroup X/J and, thus,
KX/I K
0
(X/J) (see Lemma 1.2.25 below).
Lemma 1.2.25. [4, Lemma 5.12] Let S be a semigroup and I be an ideal in
S. Then R I is an ideal in RS and RS/RI R
0
(S/I).
The analogue of Maschke Theorem (Theorem 1.1.14) for semigroup alge-
bras is the following theorem:
Theorem 1.2.26. [30, Theorem 14.24] Let K be a field and S a finite semi-
group. The following conditions are equivalent:
1. KS is a semisimple algebra
2. S
0
has a series of ideals S
0
= S
1
S
2
. . . S
n
S
n+1
= {θ}, with
each principal factor S
i
/S
i+1
M
0
(G
i
, n
i
, n
i
, P
i
), a square completely
0-simple matrix semigroup, with G
i
a finite group such that char(K)
|G
i
| and P
i
invertible in M
n
i
(KG
i
), for all i.
In the case of inverse semigroups, which are the most useful class of
semigroups in the present work, we have the following special case, that
resembles a lot Maschke Theorem:
Theorem 1.2.27. [4, Theorem 5.26] Let K be a field and S a finite inverse
semigroup. The semigroup algebra KS is semisimple if and only if char(K)
is zero or a prime not dividing the order of any subgroup of S.
The following result shows that rings of matrix type (Example 1.2.24.2)
arise naturally from matrix semigroup rings.
Theorem 1.2.28. [30, Lemma 5.1] Let R be a ring and let S be a matrix
semigroup M
0
(G, I, M, P ). Then we have that R
0
S M(RG, I, M, P ),
where we consider the entries in P as elements of the group ring RG. If S
is completely 0-simple, then M(RG, I, M, P ) is a Munn ring.
Munn rings are very imp ortant in the study of semigroup algebras over a
finite semigroup, as is shown in the following corollary:
Preliminaries
1.2. Semigroup Ring Theory 24
Corollary 1.2.29. Let S be a finite semigroup with zero element θ and with a
principal series S = S
1
S
2
. . . S
n
S
n+1
= {θ}. Then the semigroup
ring RS has a series of ideals RS = RS
1
RS
2
. . . RS
n
RS
n+1
= ,
where each factor RS
i
/RS
i+1
R
0
(S
i
/S
i+1
) is either a nilpotent ring or a
Munn ring over a group ring.
Example 1.2.30. If S := {e
1,1
, e
1,2
, e
2,2
, θ}, then
Z Z
0 Z
Z
0
S. S has
a principal series
S {e
2,2
, e
1,2
, θ} {e
1,2
, θ} {θ},
with Rees factors S/{e
2,2
, e
1,2
, θ} {e
1,1
}
0
, {e
2,2
, e
1,2
, θ}/{e
1,2
, θ} {e
2,2
}
0
and {e
12
, θ}/{θ} {e
1,2
, θ}, a null semigroup.
In order to investigate units in semigroup algebras, it is elucidative to
know when a Munn algebra over a group algebra contains an identity.
Theorem 1.2.31. [30, Corollary 5.26] Let S = M
0
(G, I, M, P ) be a Rees
matrix semigroup and K be a field. The following conditions are equivalent:
1. K
0
S has an identity;
2. I and M are finite sets of the same cardinality n and P is an invertible
matrix in M
n
(KG).
Moreover, if both conditions hold, then K
0
S M
n
(KG) and S is com-
pletely 0-simple.
Preliminaries
Chapter 2
Central Idempotents of Group
Algebras of Finite Nilpotent
Groups
In this chapter, the primitive central idempotents of a semisimple group
algebra of a finite abelian group over an arbitrary field are exhibited. After-
wards, we determine the primitive central idempotents in a complex group
algebra of a finite nilpotent group (without using group characters).
Let G be a finite abelian group of order n, and K be a field such that
char(K) n. Consider the abelian group algebra KG. From Theorem 1.1.32,
we know that KG
i
K(ζ
i
), where ζ
i
are primitive roots of unity whose
orders divide n. Clearly, the primitive idempotents of KG are the inverse
images of each tuple of the form (0, . . . , 0, 1, 0, . . . , 0) under this isomorphism.
We shall describe the primitive idempotents of KG. In particular, we obtain
a description for all cyclic codes (Definition 2.1.7) over finite fields.
For G an arbitrary finite group, the primitive central idempotents of the
complex group algebra CG are given by the formula
χ(1)
|G|
gG
χ(g
1
)g, where
χ is an irreducible complex character of G and 1 is the identity of G (Theorem
1.1.33). Though theoretically important, this description is not very useful
in practical terms, be cause, with the known methods, the computational
complexity of calculating the character table of a given finite group grows
exponentially with respect to the order of the group.
Consider now G a finite nilpotent group. The primitive central idempo-
tents in the rational group algebra QG have been determined at [14], without
making use of the character table of G. We are going to use a similar method
and the abelian case in order to find out the primitive central idempotents
in the complex group algebra CG.
Our description allows the construction of the character table of G using a
25
2.1. Primitive Idempotents of Semisimple Group Algebras of a Finite Abelian Group 26
lattice of subnormal subgroups of G. In particular, our description is helpful
in studying counterexamples to the Isomorphism Problem in group rings ([25,
Chapter 9]).
2.1 Primitive Idempotents of Semisimple
Group Algebras of a Finite Abelian
Group
Let G C
1
× . . . × C
s
be a finite abelian group of order n, with C
i
=
g
i
; g
n
i
i
= 1 the cyclic group of order n
i
generated by g
i
(Structure Theorem
of Finite Abelian Groups), and let K be a field such that char(K) n.
Define m := lcm(n
1
, . . . , n
s
). For i = 1, . . . , s, consider ζ
n
i
a primitive
root of unity of order n
i
in K, an algebraic closure of K. Given an s-tuple
of integers l = (l
1
, . . . , l
s
), with 0 l
i
n
i
1, define the polynomial
P
l
K(ζ
m
)[X
1
, . . . , X
s
] as:
P
l
=
s
i=1
n
i
1
k
i
=0
k
i
=l
i
(X
i
ζ
k
i
n
i
),
where ζ
m
is a primitive root of unity of order m. Notice that P
l
(ζ
k
1
n
1
, . . . , ζ
k
s
n
s
) =
0 if and only if k = l. This polynomial will be useful to describe the primitive
idempotents of KG.
Suppose K is an algebraically closed field such that char(K) n. From
Theorem 1.1.32, it follows that KG K . . . K, with n copies of K
on the right side (indeed, in this case, for each divisor d of n, we have that
K(ζ
d
) = K and, thus, [K(ζ
d
) : K] = 1, a
d
=
n
d
[K(ζ
d
):K]
= n
d
and
d|n
n
d
= n).
The n components of the direct sum K . . . K will be indexed by the
s-tuple of integers l = (l
1
, . . . , l
s
), with 0 l
i
n
i
1, in the following
manner: the first n
s
coordinates are the ones having l
i
= 0, for i = s, and
l
s
varying from 0 to n
s
1; the next n
s
coordinates are the ones having
l
i
= 0, for i = s, s 1, l
s1
= 1 and l
s
varying from 0 to n
s
1; the next
n
s
coordinates are the ones having l
i
= 0, for i = s, s 1, l
s1
= 2 and l
s
varying from 0 to n
s
1; and so on.
Lemma 2.1.1. Let G C
1
× . . . × C
s
be the finite abelian group of order
n, with C
i
= g
i
; g
n
i
i
= 1 a cyclic group of order n
i
generated by g
i
, and let
K be an algebraically closed field such that char(K) n. The isomorphism
KG K . . . K maps
g
x
1
1
. . . g
x
s
s
→ (. . . , ζ
x
1
k
1
n
1
. . . ζ
x
s
k
s
n
s
, . . .)
0k
i
n
i
1
,
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.1. Primitive Idempotents of Semisimple Group Algebras of a Finite Abelian Group 27
where ζ
n
i
K is a primitive root of unity of order n
i
, for each i = 1, . . . , s.
Proof. We proceed by induction on s, the number of cyclic components of
G.
When s = 1, then G = g; g
n
= 1 is a cyclic group of order n. De-
fine ζ := ζ
n
, a primitive root of the unity of order n. Consider v
i
:=
(1, ζ
i
, ζ
2i
, . . . , ζ
(n1)i
) K . . . K, for i = 1, . . . , n. We shall see that
{v
i
; i = 1, . . . , n} is a K-basis for K . . . K.
Notice that the n×n matrix having vector v
i
as its i
th
line is an invertible
Vandermonde matrix. Thus, the n vectors in the set {v
i
; i = 1, . . . , n} are
linearly independent. Since the K-dimension of K . . .K is n, we conclude
that {v
i
; i = 1, . . . , n} is a K-basis for K . . . K.
Consider the K-linear mapping
φ : KG K . . . K,
g → (1, ζ, ζ
2
, . . . , ζ
n1
).
Notice that {g
i
; i = 1, . . . , n} is a K-basis of KG and that φ(g
i
) = v
i
. So,
KG
φ
K . . . K as K-vector spaces. Clearly, φ is a ring homomorphism,
and hence KG
φ
K . . . K as rings too.
Now we consider the case where G C
1
× . . . × C
s
, with s > 1. A ssume
the result holds for any abelian group having s 1 cyclic components.
Define G
1
:= C
1
× . . . × C
s1
. We know that
KG K(G
1
× C
s
) (KG
1
)C
s
,
the isomorphisms being
α
x
g
x
1
1
. . . g
x
s1
s1
g
x
s
s
→
α
x
(g
x
1
1
. . . g
x
s1
s1
, g
x
s
s
),
α
x
(g
x
1
1
. . . g
x
s1
s1
, g
x
s
s
) →
x
s
(
x
1
,...,x
s1
α
x
g
x
1
1
. . . g
x
s1
s1
)g
x
s
s
,
where
x := (x
1
, . . . , x
s1
, x
s
), with 0 x
i
n
i
1, for each i. By the
induction hypothesis, we have that
KG
1
K . . . K,
g
x
1
1
. . . g
x
s1
s1
→ (. . . , ζ
x
1
k
1
n
1
. . . ζ
x
s1
k
s1
n
s1
, . . .)
0k
i
n
i
1
.
So, it follows that
(KG
1
)C
s
(K . . . K)C
s
KC
s
. . . KC
s
,
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.1. Primitive Idempotents of Semisimple Group Algebras of a Finite Abelian Group 28
where the last isomorphism is
x
s
(
x
1
,...,x
s1
α
x
(. . . , ζ
x
1
k
1
n
1
. . . ζ
x
s1
k
s1
n
s1
, . . .), g
x
s
s
) →
(. . . ,
α
x
ζ
x
1
k
1
n
1
. . . ζ
x
s1
k
s1
n
s1
g
x
s
s
, . . .)
0k
i
n
i
1
.
Using the cyclic group case, we have that
KC
s
. . . KC
s
K . . . K,
(. . . ,
α
x
ζ
x
1
k
1
n
1
. . . ζ
x
s1
k
s1
n
s1
g
x
s
s
, . . .) →
(. . . ,
α
x
ζ
x
1
k
1
n
1
. . . ζ
x
s1
k
s1
n
s1
ζ
x
s
k
s
s
, . . .)
0k
i
n
i
1
,
which is the desired result.
Now we describe the primitive idempotents of a semisimple group algebra
of a finite abelian group over an algebraically closed field.
Theorem 2.1.2. Let G C
1
× . . . × C
s
be a finite abelian group of order n,
with C
i
= g
i
; g
n
i
i
= 1 the cyclic group of order n
i
generated by g
i
, and let
K be an algebraically closed field such that char(K) n. Then the primitive
idempotents of the abelian group algebra KG are the elements:
e
l
:=
P
l
(g
1
, . . . , g
s
)
P
l
(ζ
l
1
1
, . . . , ζ
l
s
s
)
,
where 0 l
i
n
i
1, for i = 1, . . . , s.
Proof. The image of e
l
=
P
l
(g
1
,...,g
s
)
P
l
(ζ
l
1
1
,...,ζ
l
s
s
)
under the isomorfism KG
φ
K . . .K
specified in Lemma 2.1.1 is
φ(e
l
) = (. . . ,
P
l
(ζ
k
1
1
, . . . , ζ
k
s
s
)
P
l
(ζ
l
1
1
, . . . , ζ
l
s
s
)
, . . .)
0k
i
n
i
1
.
Since P
l
(ζ
k
1
1
, . . . , ζ
k
s
s
) = 0 if and only if k = l, we have that all the coordinates
of φ(e
l
) are zero, except the one in the position indexed by l, which equals
P
l
(ζ
l
1
1
, . . . , ζ
l
s
s
)
P
l
(ζ
l
1
1
, . . . , ζ
l
s
s
))
= 1.
Thus, φ(e
l
) = (0, . . . , 0, 1, 0, . . . , 0), with 1 in the position (l
1
, . . . , l
s
), and
hence e
l
is a primitive idempotent of KG.
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.1. Primitive Idempotents of Semisimple Group Algebras of a Finite Abelian Group 29
Corollary 2.1.3. With the same notation as in Theorem 2.1.2, suppose that
G = g; g
n
= 1 is the cyclic group of order n generated by g. Let ζ be a
primitive root of unity of order n. Then the primitive idempotents in KG
are:
e
l
:=
ζ
nl
n
n1
i=0,i=l
(g ζ
i
),
where 0 l n 1.
Proof. Notice that
P
l
(ζ
l
) =
n1
i=0
i=l
(ζ
l
ζ
i
) = ζ
l
n1
i=1
(1 ζ
i
) = ζ
l
n.
Now, s ince P
l
(g) =
n1
i=0
i=l
(g ζ
i
), the result follows directly from Theorem
2.1.2.
When the field K is not algebraically closed, exhibiting the isomorphism
KG
i
K(ζ
i
), with ζ
i
primitive roots of unity, is more complicated. In
order to avoid this, we adopt an alternative method and use the algebraically
closed case to get the primitive idempotents:
Theorem 2.1.4. Let G C
1
× . . . × C
s
be a finite abelian group of order n,
with C
i
= g
i
; g
n
i
i
= 1 the cyclic group of order n
i
generated by g
i
, and let
K be a field such that char(K) n. Define m := lcm(n
1
, . . . , n
s
). Consider
A := Aut(K(ζ
m
)|K), the Galois group of the field extension K(ζ
m
)|K. Then,
for a fixed s-tuple of integers l = (l
1
, . . . , l
s
), with 0 l
i
n
i
1, the element
e
l
defined below is a primitive idempotent of the abelian group algebra KG:
e
l
:=
σA
P
σ
l
(g
1
, . . . , g
s
)
σ(P
l
(ζ
l
1
n
1
, . . . , ζ
l
s
n
s
))
,
the sum of all Galois conjugates of P
l
(g
1
, . . . , g
s
)/P
l
(ζ
l
1
n
1
, . . . , ζ
l
s
n
s
), where P
σ
l
denotes the polynomial in K(ζ
m
)[X
1
, . . . , X
s
] obtained by applying σ to the
coefficients of P
l
. Furthermore, these are all the primitive idempotents of
KG.
Proof. From the Theorem 2.1.2, it follows that
f
l
:=
P
l
(g
1
, . . . , g
s
)
P
l
(ζ
l
1
n
1
, . . . , ζ
l
s
n
s
)
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.1. Primitive Idempotents of Semisimple Group Algebras of a Finite Abelian Group 30
is a primitive idempotent of KG, where K is an algebraic closure of K.
Therefore, f
l
is also a primitive idempotent in K(ζ
m
)G. Notice that K(ζ
m
)
is the minimal field extension K
1
of K such that all the f
l
’s belong to K
1
G.
Each σ A induces a unique automorphism σ
of K(ζ
m
)G, i.e., for α =
gG
α
g
g K(ζ
m
)G, define σ
(α) :=
gG
σ(α
g
)g. Thus, σ
(f
l
) is still a
primitive idempotent of K(ζ
m
)G and of KG.
Let e be a primitive idempotent in KG. We may write e = f
1
+ . . . + f
t
,
where f
i
are primitive idempotents in KG. Let K
2
be the minimal field
such that, for each i = 1, . . . , t, f
i
belongs to K
2
G. Take τ Aut(K
2
|K).
Applying τ
to e, we get e = τ
(e) = τ
(f
1
) + . . . + τ
(f
t
) and, by the unique
representation in K
2
G (Theorem 1.1.11), we have that, for each i = 1, . . . , t,
there exists a j = 1, . . . , t, such that τ
(f
i
) = f
j
. Thus, all the f
i
are Galois-
conjugates of one another. In fact, suppose that (after reordering) f
1
, . . . , f
s
are all conjugates of f
1
and that f
s+1
, . . . , f
t
, for some 1 < s < t. Then,
defining e
:= f
1
+ . . . + f
s
and e

:= f
s+1
+ . . . + f
t
, we have that e = e
+ e

,
with e
and e

orthogonal nonzero idempotents in KG, which contradicts the
primitivity of e. So e is exactly the sum of the distinct Galois-conjugates of
a primitive idempotent in KG, and thus, by definition, e = e
l
for some l .
Notice that the primitive idempotents e in KG and the set of distinct
e
l
’s defined exist in equal number. We conclude that each e
l
is a primitive
idempotent in KG.
Corollary 2.1.5. With the same notation as in Theorem 2.1.4, suppose
that G = g; g
n
= 1 is the cyclic group of order n generated by g. Let
ζ be a primitive root of unity of order n. Fix 0 l n 1. Consider
A := Aut(K(ζ)|K), the Galois group of the field extension K(ζ)|K. Then
the element e
l
defined below is a primitive idempotent of the abelian group
algebra KG:
e
l
:=
σ∈A
σ(ζ
nl
)
n
n1
i=0
i=l
(g σ(ζ
i
)),
Furthermore, these are all the primitive idempotents of KG.
Proof. The proof is a direct application of Theorem 2.1.4 to Corollary 2.1.3.
Example 2.1.6 (Cyclic Codes). In order to make connections between
cyclic codes and the computation of primitive idempotents for semisimple
group algebras of finite abelian groups, we need some very basic concepts o
coding theory, for which the reference is [37].
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.2. Primitive Central Idempotents of Complex Group Algebras of a Finite Nilpotent
Group 31
Let F
q
denote the finite field of q elements, with q a power of a prime
integer p. Consider the n-dimensional vector space F
n
q
, whose elements are
n-tuples a = (a
0
, . . . , a
n1
).
Definition 2.1.7. A code C is a linear subspace of F
n
q
. We call n the length
of C and dimC (as a F
q
-vector space) the dimension of C. A code C is said
to be a cyclic code if its automophism group Aut(C) contains the cyclic shift,
i.e., (c
0
, c
1
, . . . , c
n1
) C = (c
1
, . . . , c
n1
, c
0
) C.
It is common in coding theory to identify F
n
q
with the vector space P
n
of
polynomials of degree less than n over F
q
via the correspondence
a = (a
0
, . . . , a
n1
) a(x) = a
0
+ a
1
x + . . . + a
n1
x
n1
F
q
[x].
Clearly, a cyclic code C of length n may be identified with the corresponding
ideal in
F
q
[x]
(x
n
1)
.
Let G = g; g
n
= 1 be the cyclic group of order n generated by g. We
have that F
q
G
F
q
[x]
(x
n
1)
as rings, by taking the morphism g → x. Thus, we
have an immediate connection between group rings and coding theory.
Determining a cyclic code of length n over a finite field K = F
q
such
that char(K) = p n corresponds to determining an ideal in the semisimple
group algebra KG, where G is a cyclic group of order n . In this case, all the
ideals of KG are direct summands
l
k=1
(KG)e
i
k
, where l n and e
1
, . . . , e
n
are the primitive idempotents of KG as determined in Corollary 2.1.5.
2.2 Primitive Central Idempotents of
Complex Group Algebras of a Finite
Nilpotent Group
We shall first state some definitions and results needed on this section.
Definition 2.2.1. Let R be a ring with identity and let G be a group.
For e a primitive central idempotent of RG, define the subset G
e
of G as
G
e
:= {g G; eg = e}.
Definition 2.2.2. Let G be a finite group and K be a field. Define the
element ε(G) in KG by
ε(G) :=
1 , if G = {1};
M∈M(G)
(1
M) , if G = {1},
where M(G) denotes the set of all minimal nontrivial normal subgroups of
G.
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.2. Primitive Central Idempotents of Complex Group Algebras of a Finite Nilpotent
Group 32
Remark 2.2.3. Notice that if A and B are subgroups of a group G, with
A B, then
A
B =
B and (1
A)(1
B) = (1
A). So we can redefine
ε(G) as
ε(G) :=
NG
N={1}
(1
N),
when G is a nontrivial group. Notice, in particular, that if N is a nontrivial
normal subgroup of G, then (1
N)ε(G) = ε(G).
The following lemma is elementary, but extremely useful.
Lemma 2.2.4. Let G be a finite group, K be a field such that char(K) |G|,
and e be a primitive central idempotent of KG. Then:
1. G
e
is a normal subgroup of G and e
G
e
= e. Thus, e is also a primitive
central idempotent of (KG)
G
e
, and, since (KG)
G
e
K(G/G
e
), the
image e of e in K(G/G
e
) is a primitive central idempotent of K(G/G
e
);
2. if N is a normal subgroup of G, then e
N = e if and only if N G
e
;
3. G
e
= {1} if and only if ε(G)e = e;
4. if H := G
e
and N is a normal subgroup of G contained in H, then
(G/N)
e
= H/N, where e denotes the image of e in K(G/N)(we call
attention to this special case: if N is a normal subgroup of G and e is
a primitive central idempotent in K(G/N), then: (G/N)
e
= {1} if and
only if G
e
= N, where e denotes the image of e in KG).
Proof. 1. To see that G
e
is a normal subgroup of G, take h G and
g G
e
. Since e is central, we have that hgh
1
e = hgeh
1
= e. So
hgh
1
G
e
, and thus G
e
is normal in G.
By Definition 2.2.1, we have that
e
G
e
=
e
gG
e
g
|G
e
|
=
gG
e
eg
|G
e
|
=
gG
e
e
|G
e
|
=
|G
e
|e
|G
e
|
= e.
So e is a primitive central idempotent of (KG)
G
e
and e, the image of
e in K(G/G
e
), is a primitive central idempotent of K(G/G
e
).
2. Consider N a normal subgroup of G. Then
N is a central idempotent
of KG. Since e is a primitive central idempotent of KG, we have that
e
N is either equal to zero or to e.
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.2. Primitive Central Idempotents of Complex Group Algebras of a Finite Nilpotent
Group 33
Suppose e
N = e. We have that
(KG)e = (KG)
Ne K(G/N)e.
Thus we have the following diagram
KG K(G/N)
×e
K(G/N)e
(KG)e,
the maps beign
g → g,
g → ge,
ge → g
Ne = ge.
From the diagram, it follows that the ker(KG
×e
(KG)e) = G
e
and
that N ker(KG
×e
(KG)e).
If N G
e
, then
e
N =
e
gN
g
|N|
=
gN
eg
|N|
=
gN
e
|N|
=
|N|e
|N|
= e.
3. Suppose G
e
= {1}. If N is a nontrivial normal subgroup of G, then,
by 2., we have that e
N = 0. So, from Definition 2.2.2, it follows that
ε(G)e =
M∈M(G)
(1
M)e =
M∈M(G)
(e
Me) =
e = e.
Suppose G
e
= {1}. Then, by Remark 2.2.3, we have that ε(G) =
(1
G
e
)ε(G) and (G) = e(1
G
e
)ε(G) = 0.
4. This part of the Lemma follows directly from Definition 2.2.1.
The definitions and notations needed in the following lemma and theorem
are stated in Definition 1.1.31.
We need the following technical lemma ([14, Lemma 2.3]):
Lemma 2.2.5. Let G be a finite group, K be a field such that char(K) |G|,
and g G. If g
1
C
g
Z(G) = {1}, then G contains a central element z of
prime order so that
C
g
=
C
g
z.
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.2. Primitive Central Idempotents of Complex Group Algebras of a Finite Nilpotent
Group 34
Proof. By assumption there exist h G and 1 = z Z(G) so that h
1
gh =
zg. Hence, for any positive integer n we get, by induction, that h
n
gh
n
= z
n
g.
Replacing z by some power of z, if necessary, we may assume that z has
prime order. It then follows that zC
g
C
g
. So zC
g
= C
g
and therefore
C
g
=
C
g
z.
Before actually using the lemma, let us just observe that g ∈ C
G
(Z
2
(G))
implies g
1
C
g
Z(G) = {1}. In fact, suppose that, for g G, it holds that
g
1
C
g
Z(G) = {1}. Take l Z
2
(G). We have that
g
1
l
1
gl = 1 in G/Z(G)
(because Z
2
(G)/Z(G) = Z(G/Z(G)), an abelian group); in other words,
there exists z
1
Z(G) such that g
1
l
1
gl = z
1
, s o, by hypothesis, z
1
= 1.
Hence, g C
G
(Z
2
(G)).
We need a result from Jespers-Leal-Paques ([14, Proposition 2.1]). This
result is stated in the reference for the group algebra QG, where G is a finite
nilpotent group. We observe that the proof given in the article is still valid
for the case CG and we include it here for the sake of completeness.
Proposition 2.2.6. Let G be a finite nilpotent group, e CG and G
1
:=
C
G
(Z
2
(G)), the centralizer in G of the second center of G. e is a primitive
central idempotent of CG with G
e
trivial if and only if e =
gG
e
g
1
, the sum
of all distinct G-conjugates of e
1
, with e
1
a primitive central idempotent of
CG
1
satisfying
gG
((G
1
)
e
1
)
g
= {1}.
Proof. Suppose e CG is a primitive central idempotent with G
e
= {1}. By
Theorem 1.1.16, we may write e =
gG
α
g
C
g
, with each α
g
C.
For any g G with g ∈ C
G
(Z
2
(G)), by Lemma 2.2.5, there exists a
nontrivial central element w
g
G of prime order such that
C
g
=
C
g
w
g
.
Hence,
e =
g∈C
G
(Z
2
(G))
α
g
C
g
+
g∈C
G
(Z
2
(G))
α
g
C
g
w
g
.
Because G
e
= {1}, Lemma 2.2.4 yields that e = (G). Notice that
ε(G)
w
g
= 0, for, since w
g
has prime order and is central, w
g
M(G)
and, by Definition 2.2.2,
ε(G)
w
g
=
M∈M(G)
(1
M)
w
g
=
(
M∈M(G)\{w
g
}
(1
M))(1
w
g
)
w
g
=
(
M∈M(G)\{w
g
}
(1
M))(
w
g
w
g
) = 0,
i.e., ε(G)
C
g
; g C
G
(Z
2
(G))
C
, the C-subspace of CG generated by
{
C
g
; g C
G
(Z
2
(G))}.
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.2. Primitive Central Idempotents of Complex Group Algebras of a Finite Nilpotent
Group 35
So we get that
e = (G) =
g∈C
G
(Z
2
(G))
α
g
C
g
· ε(G),
and thus e
C
g
; g C
G
(Z
2
(G))
C
too.
Notice that G
1
= C
G
(Z
2
(G)) is normal in G; so if g G
1
and h C
g
, then
h G
1
. In fact, we have that h = l
1
gl, for some l G. Take x Z
2
(G). So
x
1
h
1
xh = z Z(G) and lx
1
l
1
g
1
lxl
1
gl = lz. Since Z
2
(G) is normal in
G, we have that y = lx
1
l
1
Z
2
(G), and thus y
1
g
1
yg = z = 1 (because
g G
1
= C
G
(Z
2
(G))). Hence, x
1
h
1
xh = 1 and h G
1
, as desired.
Thus, we have shown that supp(e) G
1
= C
G
(Z
2
(G)). Notice that e is
not necessarily a primitive central idempotent of CG
1
. However, it is possible
to write
e = e
g
1
1
+ . . . + e
g
n
1
,
the sum of all G-conjugates of a primitive central idempotent e
1
CG
1
.
In fact, since e CG
1
we may write, by Theorem 1.1.11, e = a
1
e
1
+
. . . + a
m
e
m
, with {e
1
, . . . , e
m
} all the primitive central ide mpotens of CG
1
and a
i
CG
1
. We have, for i = 1, . . . , m, that ee
i
is either equal to 0 or
to e
i
, because ee
i
is an idempotent and e
i
is a primitive idempotent. Hence,
after possibly reordering the e
i
’s, we have that e = e
1
+ . . . + e
k
, for some
k m. Now we only have to check that every e
i
is a G-conjugate of e
1
. For
g G, we have that e = e
g
= e
g
1
+ . . . + e
g
k
, and by the unique representation
in CG
1
(Theorem 1.1.13), we have that, for each i = 1, . . . , k, there exists
a j = 1, . . . , k, such that e
g
i
= e
j
. Thus, all the e
i
are G -c onjugate of one
another. So e is exactly the sum of the distinct G-conjugates of e
1
.
Observe that ((G
1
)
e
1
)
g
i
= (G
1
)
e
g
i
1
(for g (G
1
)
e
g
i
1
ge
g
i
1
= e
g
i
1
g
g
1
i
e
1
= e
1
g
g
1
i
(G
1
)
e
1
g ((G
1
)
e
1
)
g
i
). Hence, it easily follows
that
n
i=1
((G
1
)
e
1
)
g
i
= G
e
= {1}. This proves the necessity of the conditions.
Conversely, suppose that G is a finite nilpotent group, that e
1
is a primi-
tive central idempotent of CG
1
, where G
1
:= C
G
(Z
2
(G)), and that
gG
((G
1
)
e
1
)
g
= {1}. Let e := e
g
1
1
+ . . . + e
g
n
1
be the sum of all dis-
tinct G-conjugates of e
1
. Clearly, e is a central idempotent of CG and
G
e
=
gG
((G
1
)
e
1
)
g
= {1}.
To see that e is primitive, write e = f
1
+. . .+f
k
, a sum of primitive central
idempotents of CG. For any nontrivial central subroup N of G, by Lemma
1.1.17,
N is a central idempotent of CG
1
(for N Z(G) C
G
(Z
2
(G)) = G
1
),
so either
Ne
1
= 0 or
Ne
1
= e
1
. However, the latter is impossible, as it
implies, by Lemma 2.2.4, that N (G
1
)
e
1
and thus N
gG
((G
1
)
e
1
)
g
=
{1}. So we get that
Ne
1
= 0. Recall that, for a nilpotent group, every
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.2. Primitive Central Idempotents of Complex Group Algebras of a Finite Nilpotent
Group 36
minimal normal subgroup is central ([25, Corollary 1.5.19]). Thus
ε(G)e
1
=
M∈M(G)
(1
M)e
1
=
M∈M(G)
(e
1
Me
1
) = e
1
.
The same argument us ed above to see that
Ne
1
= 0 works to show that
Ne
g
i
1
= 0, for any G-conjugate e
g
i
1
of e
1
. Consequently, ε(G)e = e, and
hence, by the unique representation in CG (Theorem 1.1.13), ε(G)f
1
= f
1
.
Therefore, by Lemma 2.2.4 again, G
f
1
= {1}, and, by the first part of the
proof, f
1
CG
1
. In the first part of the proof, we saw that a primitive
central idempotent f
1
, having G
f
1
= {1}, may be written as the sum of all
the distinct G-conjugates of e
1
. So, by the definition of e, it follows that
e = f
1
is a primitive central idempotent of CG.
The following theorem yields an explicit formula for the primitive central
idempotents in CG when G is a finite nilpotent group.
Theorem 2.2.7. Let G be a finite nilpotent group. The primitive central
idempotents of the group algebra CG are precisely all elements of the form
gG
(e
H
m
)
g
,
the sum of all distinct G-conjugates of e, where e is an element of CG
m
such
that e (the image of e in C(G
m
/H
m
)) is a primitive central idempotent in
C(G
m
/H
m
), having (G
m
/H
m
)
e
= {1}. The groups H
m
and G
m
are subgroups
of G satisfying the following properties:
1. H
0
H
1
. . . H
m
G
m
. . . G
1
G
0
= G,
2. for 0 i m , H
i
is a normal subgroup of G
i
, G
i
/H
i
is not abelian for
0 i < m, and G
m
/H
m
is abelian,
3. for 0 i m 1, G
i+1
/H
i
= C
G
i
/H
i
(Z
2
(G
i
/H
i
)),
4. for 1 i m,
xG
i1
/H
i1
H
x
i
= H
i1
.
Proof. Let us first show that the element defined above, satisfying the listed
conditions, is in fact a primitive central idempotent of CG. By condition 2,
G
m
/H
m
is an abelian group. Let f
m
:= e, a primitive central idempotent in
C(G
m
/H
m
), having (G
m
/H
m
)
e
= {1}. Since C(G
m
/H
m
) (CG
m
)
H
m
, we
have that f
m
:= e
H
m
is a primitive central idempotent of (CG
m
)
H
m
and,
thus, it is also a primitive central idempotent of CG
m
. From (G
m
/H
m
)
e
=
{1}, we have, by Lemma 2.2.4, that (G
m
)
f
m
= H
m
; so (G
m
/H
m1
)
f
m
=
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.2. Primitive Central Idempotents of Complex Group Algebras of a Finite Nilpotent
Group 37
H
m
/H
m1
(where f
m
is any preimage of f
m
in G
m
/H
m1
). Define f
m1
:=
g G
m1
/H
m1
f
m
g
, the sum of all distinct G
m1
/H
m1
-conjugates of f
m
.
Then it is a central idempotent of C(G
m1
/H
m1
). From condition 4,
gG
m1
/H
m1
(G
m
/H
m1
)
f
m
g
=
gG
m1
/H
m1
(H
m
/H
m1
)
g
= {1}.
Conditions 3 and 4 provide the hypotheses for the Proposition 2.2.6, which
yields that f
m1
is primitive in C(G
m1
/H
m1
) (CG
m1
)
H
m1
. Thus,
f
m1
:= (
gG
m1
f
g
m
)
H
m1
, the image of f
m1
in (CG
m1
)
H
m1
, is a prim-
itive central idempotent of CG
m1
. We also have, by condition 2, that:
f
m1
= (
gG
m1
f
g
m
)
H
m1
=
gG
m1
(f
m
H
m1
)
g
=
gG
m1
(e
H
m
H
m1
)
g
=
gG
m1
(e
H
m
)
g
,
By induction, we obtain that f
0
=
gG
(e
H
m
)
g
is a primitive central idem-
potent of CG.
Now, let f
0
:= d be a primitive central idempotent of CG, where G is a
finite nilpotent group with nilpotency class c. Then H
0
:= G
d
is a normal
subgroup of G
0
:= G by Lemma 2.2.4, and, since f
0
H
0
= f
0
, we have that f
0
is
a primitive central idempotent of (CG
0
)
H
0
. From (CG)
H
0
C(G
0
/H
0
), we
get that f
0
, the image of f
0
in C(G
0
/H
0
), is a a primitive central idemp otent
of C(G
0
/H
0
). Clearly, (G
0
/H
0
)
f
0
= {1}.
If G
0
/H
0
is an abelian group, we know f
0
from Theorem 2.1.2 and, triv-
ially, d = f
0
=
gG
(f
0
H
0
)
g
, because f
0
H
0
= f
0
and f
0
is central.
If G
0
/H
0
is not an abelian group, let G
1
be the unique subgroup of G
0
such that G
1
/H
0
= C
G
0
/H
0
(Z
2
(G
0
/H
0
)) = G
0
/H
0
. Then, by Proposition
2.2.6, we get:
f
0
=
gG
0
/H
0
f
1
g
,
where f
1
is a primitive central idempotent of C(G
1
/H
0
), and
xG
0
/H
0
(H
1
/H
0
)
x
= {1},
with H
1
the unique subgroup of G
0
containing H
0
such that H
1
/H
0
=
(G
1
/H
0
)
f
1
. So H
1
is a normal subgroup of G
1
. Notice that, from the def-
inition of G
1
/H
0
, its nilpotency class is at most c 1. Since C(G
1
/H
1
)
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.3. Some Questions for Further Investigation 38
(C(G
1
/H
0
)
(H
1
/H
0
), we have that f
1
, the image of f
1
in C(G
1
/H
1
), is a prim-
itive central idempotent of C(G
1
/H
1
), having (G
1
/H
1
)
f
1
= {1}. If G
1
/H
1
is an abelian group, then we know f
1
from Theorem 2.1.2. If G
1
/H
1
is not
an abelian group, the result follows by induction on the nilpotency class c of
G.
Remark 2.2.8. Notice that the statement and the proof of Theorem 2.2.7
are still valid if we replace C by any algebraically closed field K provided that
char(K) does not divide the order of the group. However, historically, the
complex case is of particular interest. So, we decided to state the theorem in
this context.
Remark 2.2.9. Given a finite nilpotent group G, we know the primitive
central idempotents e
i
of CG from Theorem 2.2.7. We can then readily com-
pute the irreducible complex characters χ
i
of G from the formula (Theorem
1.1.33)
e
i
=
χ
i
(1)
|G|
gG
χ
i
(g
1
)g,
obtaining the character table of G.
It is known that if two finite groups G and H have the same character
table, then CG CH ([25, Theorem 5.22]). Thus our desc ription of the
primitive central idempotents of CG is useful in studying counterexamples
to the Isomorphism Problem in group rings ([25, Chapter 9]).
2.3 Some Questions for Further
Investigation
The results of [14], in which we base our method, were extended and
simplified in [29], providing an algorithm using only elementary methods
for calculating the primitive central idempotents of QG, when G is a finite
nilpotent group, among other cases, but not of CG. These improvements
were implemented in a package ([27]) of programs for GAP System, version
4. An experimental comparison of the speed of the algorithm in [27] and
the character method (computing primitive central idempotents from the
character table of the group) was presented in [28] and showed that the first is
usually faster. These improvements, however, do not carry on automatically
to the complex case.
Notice that the computational complexity of the method proposed in
Theorem 2.2.7 is still not known. It provides, however, a theoretic alternative
to the usual character method that might be simpler.
Central Idempotents of Group Algebras of Finite Nilpotent Groups
2.3. Some Questions for Further Investigation 39
Hence, calculating the computational complexity of the proposed method
and trying to adapt the ideas in [29] to the complex case may be natural
directions to follow in further studies of the subject.
Central Idempotents of Group Algebras of Finite Nilpotent Groups
Chapter 3
The Normalizer of a Finite
Semigroup and Free Groups in
the Unit Group of an Integral
Semigroup Ring
Given a group G and a commutative ring R, one of the central problems in
Group Ring Theory is deciding to which extent the group ring RG reflects the
properties of the group G. More precisely, one might wonder: is it true that
if RG RH as R-algebras, then G H? This problem was stated for the
first time in Higman’s P h.D. Thesis [13] and is known as the Isomorphism
Problem ([25, Chapter 9]). The answer strongly depends on the ring R
(for instance, from Theorem 1.1.32, it is known that if K is an algebraicaly
closed field, G and H are both finite abelian groups having the same order,
and |G| = |H| char(K), then KG KH) and early results seemed to
suggest that, for a given family of groups, it might be possible to obtain
an adequate field for which the isomorphism problem would have a positive
answer. However, Dade gave an example in [5] of two nonisomorphic groups
such that their respective group algebras over any field are isomorphic.
Of primary importance is the case when R = Z, for if ZG ZH, then
RG RH as R-algebras, for any commutative ring R.
The normalizer of the trivial units ±G in the unit group of an integral
group ring ZG of a finite group G has turned out to be very useful ([15],
[24]) in tackling the isomorphism problem for integral group rings. In par-
ticular, Hertweck’s investigations in [12] have led to a counterexample to the
isomorphism problem.
Quite naturally, the same problem also makes sense for semigroup rings
([25, Chapter 9]). Studying the normalizer for semigroup rings might be
40
3.1. The Normalizer of a Semigroup 41
helpful in investigating the isomorphism problem for semigroup rings them-
selves, or for group rings, via the connection between these two subjects
provided by partial group rings ([6]). However, in the context of semigroup
rings, very little is known. When we want to investigate this problem for
semigroup rings in a similar way as was done for group rings, we need a
suitable concept of normalizer, as we can no longer speak of trivial units.
In this chapter, we introduce a concept of normalizer of a semigroup S in
the unit group of the integral semigroup ring ZS. We show that this defini-
tion coincides with the normalizer of a group in case of integral group rings
and behaves very much like it in the class of semigroups that are the most
related with groups, namely inverse semigroups. These semigroups have a
natural involution with which we can extend Krempa’s characterization of
the normalizer of the trivial units using the classical involution ([36, Proposi-
tion 9.4]). We will describe the torsion part of the normalizer and study the
double normalizer. Just like in group rings ([8]), the normalizer of a semi-
group contains the finite conjugacy center and the second center of the unit
group of the integral semigroup ring. We will pose the normalizer problem for
integral semigroup rings and solve it for finite Malcev nilpotent semigroups
such that the rational semigroup ring is semisimple. Furthermore, just like
in integral group rings ([36, Proposition 9.5]), we get that the normalizer of a
semigroup is a finite extension of the center of the semigroup ring. All of this
indicates that our concept of normalizer of a semigroup behaves as desired.
Also, using the natural involution on inverse semigroups, we will con-
struct free groups in the unit group of the integral semigroup ring, following
Marciniak and Sehgal [23], using a bicyclic unit and its image under the
involution.
Semigroup rings of inverse semigroups are a wide and interesting class
containing for example matrix rings and partial group rings, for which the
isomorphism problem recently has been investigated (see [6] and [7]).
3.1 The Normalizer of a Semigroup
We start by giving the definition of the normalizer of a semigroup in
the unit group of its integral semigroup ring. This definition coincides with
the normalizer of the trivial units in the case of an integral group ring and
behaves very much like it for some semigroups. Many results that hold for
the normalizer of the trivial units in the unit group of an integral group ring
will be extended to the context of integral semigroup rings by means of this
definition.
Let S be a semigroup. Consider the contracted integral semigroup ring
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 42
with identity (Z
0
S)
1
. We denote by U((Z
0
S)
1
) the group of units of (Z
0
S)
1
.
Define the normalizer of ±S as
N(±S) := {u U((Z
0
S)
1
); usu
1
±S, for all s ±S},
which is clearly a semigroup.
Let M
0
be the subsemigroup of S which is the union of all the maximal
subgroups of S (see Definition 1.2.6) with a zero θ adjoined, i.e.,
M
0
:= (
i
U(E
i,i
SE
i,i
)) {θ},
where the E
i,i
are the idempotents of S. We can hence consider N(±M
0
)
N(±M
0
) := {u U((Z
0
S)
1
); usu
1
±M
0
, for all s ±M
0
}.
More generally, let H be a subset of U((Z
0
S)
1
). Define the normalizer of
±H in U((Z
0
S)
1
) as
N(±H) := {v U((Z
0
S)
1
); v
1
uv ±H , for all u ±H}.
As a special case of this definition, we call attention to N(N(S).
Given a group G, denote by the classical involution in the integral group
ring ZG (Definition 1.1.3), i.e., for α =
gG
α
g
g ZG, with α
g
Z, we
have that α
:=
gG
α
g
g
1
. Denote by U(ZG) the group of units in ZG
and by N
U(ZG)
(±G) the normalizer of the trivial units ±G in U(ZG), i.e.,
N
U(ZG)
(±G) := {u U(ZG); ugu
1
±G, for all g ±G}.
Krempa’s characterization of the normalizer in group rings ([36, Propo-
sition 9.4]) states that an element u U(ZG) belongs to the normalizer
N
U(ZG)
(±G) if and only if uu
is a central element in U(ZG). So, there
is a close connection between the normalizer and the classical involution.
Therefore, inverse semigroups (Definition 1.2.6) are the most interesting and
suitable class of semigroups for investigating normalizers in semigroup rings.
For an inve rse semigroup S (Definition 1.2.6), we c an define the morphism
: S S; s → s
,
where s
is the unique element in S such that ss
s = s and s
ss
= s
(as
in Definition 1.2.6). Clearly, is an involution in S (see [4, Lemma 1.18])
and can be extended linearly to an involution in (Z
0
S)
1
, with (1) := 1. We
will often denote (a) by a
, for a (Z
0
S)
1
. Notice that, if a (Z
0
S)
1
and
supp(a) G, a subgroup of S, then a
= a
. Also, if u U((Z
0
S)
1
), then it
is easy to see that (u
)
1
= (u
1
)
.
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 43
Let S be a finite inverse semigroup. It is well known ([4, §3.3, Exercise 3])
that every principal factor of S is a Brandt semigroup (i.e., a matrix semi-
group of the form M
0
(G, n, n, I
n
), where I
n
is the n × n identity matrix and
G is a maximal subgroup of S, according to Theorem 1.2.14 and Proposition
1.2.8). Moreover, the rational s emigroup algebra QS is semisimple (Theorem
1.2.27). By Corollary 1.2.29, QS has a series of ideals QS = QS
1
QS
2
. . . QS
s
QS
s+1
= Qθ, where S
i
are ideals in a principal series of S
and S
i
/S
i+1
M
0
(G
i
, n, n, I
n
) and QS
i
/QS
i+1
Q
0
(S
i
/S
i+1
) M
n
i
(QG
i
),
with G
1
, . . . , G
s
the maximal subgroups of S (up to isomorphism). We have
that
Q
0
S = Q
0
S
1
Q
0
S
1
Q
0
S
s
× Q
0
S
s
Q
0
S
1
Q
0
S
s
× M
n
s
(QG
s
),
and
Q
0
S
1
Q
0
S
i+1
Q
0
S
1
Q
0
S
i
×
Q
0
S
i
Q
0
S
i+1
Q
0
S
1
Q
0
S
i
× Q
0
(S
i
/S
i+1
)
Q
0
S
1
Q
0
S
i
× M
n
i
(QG
i
),
for i = 1, . . . , s1. Thus, (Q
0
S)
1
M
n
1
(QG
1
). . .M
n
s
(QG
s
). Repeating
the same argument for Z, we have that (Z
0
S)
1
M
n
1
(ZG
1
). . .M
n
s
(ZG
s
).
Therefore U((Z
0
S)
1
) GL
n
1
(ZG
1
) . . . GL
n
s
(ZG
s
). Hence, we can
work “coordinatewise” and we will therefore make the reduction to S a
finite Brandt semigroup and G a maximal subgroup of S. In this case,
(Z
0
S)
1
M
n
(ZG) and, for a = (a
i,j
) (Z
0
S)
1
, we have that (a
i,j
)
= (a
j,i
).
Given a group G, we denote by Mon(±G) the group of monomial matrices
over ±G. Notice that for a Mon(±G) we have that
(a
)
i,j
=
a
1
j,i
, if a
j,i
= 0;
0, if a
j,i
= 0.
Denote by Diag(±G) the subgroup of Mon(±G) consisting of matrices over
±G having nonzero elements only on the diagonal, and denote by Scal(±G)
the matrices of Diag(±G) having the same element on the diagonal.
Remark 3.1.1 (Partial Group Rings). We recall the definition of partial
group rings and some properties, which will make it possible to relate these
objects with the present work.
Definition 3.1.2. Given a group G and a ring R with identity, we consider
the semigroup S
G
generated by the set of symbols {[g]; g G}, with the
following relations:
1. [s
1
][s][t] = [s
1
][st];
2. [s][t][t
1
] = [st][t
1
];
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 44
3. [s][e] = [s];
4. [e][s] = [s];
for all s, t G. The partial group ring R
par
G is the semigroup ring of S
G
over R, i.e.
R
par
G := RS
G
.
(Notice that relation (4) follows from the previous ones, and thus could be
removed from the list.)
Given a group G, the semigroup S
G
is an inverse semigroup ([10, Theorem
3.4]) and does not contain a zero element.
Remark 3.1.3. Let S be a finite semigroup. If all principal factors of S are
of the form M
0
(G, n, n, P ), with P invertible in M
n
(ZG), then, by Theorem
1.2.26, (Q
0
S)
1
is a semisimple semigroup algebra and (Q
0
S)
1
M
n
1
(QG
1
)
. . . M
n
s
(QG
s
), where G
1
, . . . , G
s
are the maximal subgroups of S (up to
isomorphism). Again, (Z
0
S)
1
M
n
1
(ZG
1
). . .M
n
s
(ZG
s
). By considering
the ring isomorphism
f : ZM
0
(G, n, n, I
n
) ZM
0
(G, n, n, P ) defined by A → f(A) := AP
1
,
we can work “coordinatewise”, and transport all the results obtained on
inverse semigroups to such a semigroup S.
3.1.1 Characterization of N(±S) and Some Results
Recall that, for any semigroup , all maximal subgroups are ismomorphic
(see Definition 1.2.6). In case S is a Rees matrix semigroup over a group G,
then all the maximal semigroups are isomorphic to G (see Proposition 1.2.8).
We shall now characterize the normalizer of a semigroup and prove several
interesting properties.
Theorem 3.1.4. Let S be a finite Brandt semigroup, let M denote the union
of all maximal subgroups of S, and let G be a maximal subgroup of S. We
have that:
1. N(±S) = Scal(N
U(ZG)
(±G))Mon(±G) and N(±S) N(±M
0
);
2. N(±M
0
) = Mon(N
U(ZG)
(±G));
3. if u N(±M
0
) then uu
Diag(Z(U(ZG)));
4. if u N(±S) then uu
Z(U(Z
0
S)
1
)).
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 45
Proof. Being a Brandt semigroup, we have that (see Theorem 1.2.14) S
M
0
(G, n, n, I
n
) and M
0
{s = ge
i,i
M
0
(G, n, n, I
n
); g G, i = 1, . . . , n},
where I
n
is the n × n identity matrix and e
i,j
are matrix units (Example
1.2.2.1). Let u =
n
i,j=1
u
i,j
e
i,j
U((Z
0
S)
1
).
1. For u to be in N(±S), we need that for all s ±S, there exists a t ±S,
such that us = tu. Now, s = ge
k,l
and t = he
m,p
, for some g, h ±G and
then us =
i
u
i,k
ge
i,l
and tu =
j
hu
p,j
e
m,j
.
Thus, us = tu means that
u
m,k
g = hu
p,l
;
u
i,k
= 0, for all i = m;
u
p,j
= 0, for all j = l.
When we take k = l (i.e., s = ge
k,k
±M
0
), we deduce that
u
m,k
g = hu
p,k
;
u
i,k
= 0, for all i = m;
u
p,j
= 0, for all j = k.
()
Suppose that m = p. Then we get that u
p,k
= 0; hence, u
p,j
= 0 for
1 j n, which contradicts that u is a unit.
Therefore, m = p (i.e., t = he
m,m
±M
0
) and () becomes
u
m,k
g = hu
m,k
;
u
i,k
= 0, for all i = m;
u
m,j
= 0, for all j = k.
Since g and k are arbitrary, we get that u is a monomial matrix
k
u
m
k
,k
e
m
k
,k
, with u
m
k
,k
N
U(ZG)
(±G).
Now, consider s = ge
k,l
±S, with k = l (i.e., s ±S \ ±M
0
). So
u N(±S), if
uge
k,l
u
1
= u
m
k
,k
gu
1
m
l
,l
e
m
k
,m
l
±S
(since u
1
=
i
u
1
m
i
,i
e
i,m
i
). As u
m
k
,k
N
U(ZG)
(±G), we have u
m
k
,k
gu
1
m
l
,l
=
hu
m
k
,k
u
1
m
l
,l
±G, for some h ±G; so u
m
k
,k
u
1
m
l
,l
must be in ±G. Hence, all
entries in u differ up to trivial units. Thus u Scal(N
U(ZG)
(±G))Mon(±G).
So, N(±S)) Scal(N
U(ZG)
(±G))Mon(±G).
Now, to see that Scal(N
U(ZG)
(±G))Mon(±G) N(±S), consider u
Scal(N
U(ZG)
(±G))Mon(±G), i.e., u =
n
i,j=1
va
i,j
e
i,j
monomial, with v
N
U(ZG)
(±G) and a
i,j
= 0 or a
i,j
±G. For s = ge
k,l
±S, with g
±G, we have that us =
i
va
i,k
ge
i,l
= va
i
k
,k
ge
i
k
,l
, where a
i
k
,k
is the only
nonzero element in the k
th
column of u. Since v N
U(ZG)
(±G), we have
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 46
that us = va
i
k
,k
ge
i
k
,l
= hva
j
l
,l
e
i
k
,l
, where a
j
l
,l
is the only nonzero element
in the l
th
column of u, for h := va
i
k
,k
ga
1
j
l
,l
v
1
±G. So, us = tu, with
t = he
i
k
,j
l
±S.
2. Notice that the proof that N(±M
0
) Mon(N
U(ZG)
(±G)) is contained
in the proof of 1., as we have seen that for u =
n
i,j=1
u
i,j
e
i,j
U((Z
0
S)
1
)
and s = ge
k,k
±M
0
, us = tu automatically implies that t = he
m,m
±M
0
(hence, u N(±M
0
)) and u Mon(N
U(ZG)
(±G)).
To see that Mon(N
U(ZG)
(±G)) N(±M
0
), take u Mon(N
U(ZG)
(±G)),
i.e., u =
n
i,j=1
u
i,j
e
i,j
monomial, with u
i,j
= 0 or u
i,j
N
U(ZG)
(±G), and
s = ge
k,k
±M
0
, with g ±G. We have that us =
i
u
i,k
ge
i,k
= u
i
k
,k
ge
i
k
,k
,
where u
i
k
,k
is the only nonzero element in the k
th
column of u. Since u
i
k
,k
N
U(ZG)
(±G), we have that us = u
i
k
,k
ge
i
k
,l
= hu
i
k
,k
e
i
k
,k
, for some h ±G.
So, us = tu, with t = he
i
k
,i
k
±M
0
.
3. Take u N(±M
0
). From the first part of the proof, we know that
u Mon(N
U(ZG)
(±G)), i.e., u = (u
i,j
) monomial, with u
i,j
= 0 or u
i,j
N
U(ZG)
(±G). So u
= (u
j,i
). By computing uu
, we get a diagonal matrix
with u
i,j
u
i,j
in the (i, i) position, when u
i,j
= 0. From [36, Proposition 9.4],
we know that u
i,j
u
i,j
Z(U(ZG)). So, we have the desired result.
4. Following the same lines of 3., we get the analogue result for N(±S).
We get, as an easy but important consequence, that an element of the
normalizer commutes with its image under the involution .
Corollary 3.1.5. Let S be a finite Brandt semigroup, l et M denote the
union of all maximal subgroups of S, and let G be a maximal subgroup of S.
If u N(±M
0
), then uu
= u
u.
Proof. Take u N(±M
0
), say u = (u
i,j
) monomial, with u
i,j
= 0 or u
i,j
N
U(ZG)
(±G). From Theorem 3.1.4, (3), uu
Diag(Z(U(ZG))), i.e., for
each i, j such that u
i,j
= 0, we have that u
i,j
u
i,j
Z(U(ZG)). So, for all i, j,
(u
i,j
u
i,j
)u
1
i,j
(u
i,j
)
1
= u
1
i,j
(u
i,j
u
i,j
)(u
i,j
)
1
= 1.
Thus u
i,j
u
i,j
= u
i,j
u
i,j
, for all i, j, and we have that uu
= u
u.
For group rings, we know that the only unitary units (Definition 1.1.30)
for the classical involution are the trivial units (Proposition 1.1.34). We now
describe the analogous -unitary elements”.
Theorem 3.1.6. Let S be a finite Brandt semigroup and G a maximal sub-
group of S. For v (Z
0
S)
1
, vv
= 1 if and only if v Mon(±G).
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 47
Proof. This proof is very similar to the proof of Proposition 1.1.34.
Being a Brandt semigroup, we have that (see Theorem 1.2.14) S
M
0
(G, n, n, I
n
) and (Z
0
S)
1
M
n
(ZG) (see Example 1.2.24).
Let v = (v
i,j
) (Z
0
S)
1
, with v
i,j
=
gG
v
i,j
(g)g ZG. From vv
= 1 =
I
n
, we get in particular that, for all i,
j
v
i,j
v
i,j
=
j
(
gG
v
i,j
(g)
2
) = 1.
Hence, for each i, exactly one v
i,j
(g) = 1, i.e., for each i, exactly one v
i,j
is
a trivial unit and all the other ones are zero. Again, from vv
= I
n
, we can
deduce relations between the rows and columns from which it follows that
v Mon(±G).
Cleary, if v M on(±G), then v
= v
1
.
Next, we prove some results for the normalizer in semigroup rings, that
were proved for group rings in [18], [22] , [24].
The following Lemma is, in a certain sense, the semigroup ring analogue
of a famous corollary of Berman–Higman Lemma for group rings (Corollary
1.1.36). It will be very helpful on many of the results to be proved, and it
has an interesting immediate Corollary.
Lemma 3.1.7. Let S be a finite Brandt semigroup and G a maximal subgroup
of S. If c D iag(Z(U(ZG))) and c is a torsion unit, then c Diag(±Z(G)).
Proof. Take c Diag(Z(U(ZG))) a torsion unit, say c = (c
i,j
), with c
i,j
= 0,
if i = j, and c
i,i
Z(U(ZG)) torsion units in ZG. We have from Corollary
1.1.37, that, for all i, c
i,i
±Z(G), i.e., c D iag(±Z(G)).
Corollary 3.1.8. Let S be a finite Brandt semigroup, l et M denote the
union of all maximal subgroups of S, and let G be a maximal subgroup of S.
If u N(±M
0
), then either uu
has infinite order, or uu
= 1 and, in this
case, u Mon(±G).
Proof. Take u N(±M
0
), say u = (u
i,j
) monomial, with u
i,j
= 0 or u
i,j
=
gG
u
i,j
(g)g N
U(ZG)
(±G). From Theorem 3.1.4, (3), we know that uu
=
c D iag(Z(U(ZG))). Suppose c is a torsion unit. We have, from Lemma
3.1.7, that c = (c
i,j
) Diag(±Z(G)).
For each i, c
i,i
= u
i,j
u
i,j
is a trivial unit with c
i,i
(1) =
gG
u
i,j
(g)
2
= 0.
It follows that, for each i, c
i,i
= 1, i.e., uu
= 1. From Theorem 3.1.6, it now
follows that u Mon(±G).
Denote by T (N(±M
0
)) the set of torsion units in N(±M
0
). We can prove
that the elements in Mon(±G) are the only torsion elements in N(±M
0
) and
in N(±S).
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 48
Proposition 3.1.9. Let S be a finite Brandt semigroup, let M denote the
union of all maximal subgroups of S, and let G be a maximal subgroup of S.
We have that T (N(±M
0
)) = Mon(±G) = T (N(±S)).
Proof. Take u T (N(±M
0
)). From Corollary 3.1.5, we know that uu
is
a torsion unit and, from Corollary 3.1.8, we get uu
= 1, and thus u
Mon(±G).
The other inclusion is obvious.
The proof is similar for T (N(±S)).
We can now characterize when the normalizer coincides with the torsion
units.
Proposition 3.1.10. Let S be a finite Brandt semigroup, let M denote the
union of all maximal subgroups of S, and let G be a maximal subgroup of S.
The following are equivalent:
1. N(±M
0
) = T(N(±M
0
));
2. N(±S) = T (N(±S));
3. Z(U(ZG)) = ±Z(G).
Proof. From 1. to 2., it is obvious, using that N(±S) N(±M
0
) and
Proposition 3.1.9.
Now, suppose 2. is true. Since Z(U(Z
0
S)
1
)) Scal(Z(U(ZG))) is con-
tained in N(±S) = T (N(±S)), we have by Lemma 3.1.7 that Z(U(ZG)) =
±Z(G).
If 3. holds, then from Theorem 3.1.4, (3) it follows that for all u
N(±M
0
), uu
Diag(±Z(G)); in particular, uu
has finite order. Thus,
from Corollary 3.1.8, u Mon(±G) T (N(±M
0
)). The other inclusion is
always true.
For a finite group G, a well known result due to Krempa [36, Proposition
9.4] states that: for u U(ZG), we have that u N
U(ZG)
(±G) uu
Z(U(ZG)). We will prove a similar result for N(±Mon(G)), but first we
need the following lemma.
Lemma 3.1.11. Let S be a finite Brandt semigroup, S = M({1}, 2, 2, I
2
)
and G a maximal subgroup of S. If t U((Z
0
S)
1
) is such that ta = at, for
all a Mon(±G), then t Z(U(Z
0
S)
1
)).
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 49
Proof. We have that S M
0
(G, n, n, I
n
), with I
n
the n × n identity matrix.
We divide the proof in two parts.
Part 1: If t (Z
0
S)
1
and ta = at, for all a Mon(±G), then there exist
α Z(ZG) and β Z
G such that t = (t
i,j
), with t
i,j
=
α, if i = j
β, if i = j
We prove this by induction on n.
For n = 1 the result is obvious.
So, assume the result is valid for n 1 and we will verify it for n. Take
t (Z
0
S)
1
M
n
(ZG) such that ta = at, for all a Mon
n
(±G) (i.e., the
monomial n × n matrices over ±G). So, t =
t
1,1
. . . t
1,n
.
.
.
t
t
n,1
, where
t
M
n1
(ZG) and it is easy to see that t
b = bt
, for all b Mon
n1
(±G),
as e
1,1
+ b Mon
n
(±G). Hence by the induction hypothesis, there exist
α Z(ZG) and β Z
G such that t
i,j
=
α, if i = j
β, if i = j
Take a =
g
i
e
i,i
Mon(±G). We have that ta =
t
i,j
g
j
e
i,j
and
at =
g
i
t
i,j
e
i,j
. Thus, for every i and j,
t
i,j
g
j
= g
i
t
i,j
.(∗∗)
This means, in particular, that t
i,i
g
i
= g
i
t
i,i
and, since this is valid for an
arbitrary g
i
G, we have that t
i,i
Z(ZG), for every i. For i = j, we get
that t
i,j
Z
G.
Now, take a =
g
i
e
i,n+1i
Mon(±G). Then ta =
t
i,n+1j
g
n+1j
e
i,j
and at =
g
i
t
n+1i,j
e
i,j
. Thus, for every i and j, t
i,n+1j
g
n+1j
= g
i
t
n+1i,j
.
So, for all j, g
1
t
n,j
= t
1,n+1j
g
n+1j
= g
1
t
1,n+1j
, the last equality following
from (∗∗). Hence, for all j, t
1,n+1j
= t
n,j
, and, by the induction hypoth-
esis, for j = 1, n, we have that t
1,j
= t
n,n+1j
= β. Similarly, for all i,
g
i
t
n+1i,1
= t
i,n
g
n
= g
i
t
i,n
, the last equality following from (∗∗). Hence, for
all i, t
(n+1i),1
= t
i,n
, and, by the induction hypothesis, for i = 1, n, we have
that t
i,1
= t
(n+1i),n
= β. Also, we get t
1,1
= t
n,n
= t
i,i
= α, by the induction
hypothesis again.
So, the only entries in t that are still unknown are t
1,n
and t
n,1
.
Consider a = g
1
e
1,1
+
n
i=2
g
i
e
i,n+2i
Mon(±G). Then we have that
ta =
n
i=1
(t
i,1
g
1
e
i,1
+
n
j=2
t
i,n+2j
g
n+2j
e
i,j
) and at =
n
j=1
(g
1
t
1,j
e
1,j
+
n
i=2
g
i
t
n+2i,j
e
i,j
). Thus, g
1
t
1,n
= t
1,2
g
2
= g
2
t
1,2
, the last equality following
from (∗∗). Hence, t
1,n
= t
1,2
= β, by the induction hypothesis.
Finally, consider a = g
n
e
n,n
+
n1
i=1
g
i
ei, n i Mon(±G). We have
that ta =
n
i=1
(t
i,n
g
n
e
i,n
+
n1
j=1
t
i,nj
g
nj
e
i,j
) and at =
n
j=1
(g
n
t
n,j
e
n,j
+
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 50
n1
i=1
g
i
t
ni,j
e
i,j
). Thus, g
n
t
n,1
= t
n,n1
g
n1
= g
n
t
n,n1
, the last equality
following from (∗∗). Hence, t
n,1
= t
n,n1
= β, by the induction hypothesis.
And this concludes the proof of the first part of the Lemma.
Part 2: If t U((Z
0
S)
1
) is such that t = (t
i,j
), with t
i,j
=
α, if i = j
β, if i = j
,
for some α Z(ZG) and β = b
G Z
G, then t Z(U((Z
0
S)
1
)).
The case n = 1 is trivial.
For the rest of the proof, we assume n > 2 or |G| > 1.
Take t as in the statement above. Notice that, by performing elementary
operations on t, det(t) is multiplied by ±1 (since we are working on integral
matrices). Then, by bringing t to its row-echelon form, it is easy to see
that det(t) = ±(α β)
n1
(α + (n 1)β). Since t is a unit, we have that
det(t) U(ZG). Consider ε the augmentation mapping in ZG. If we take
ε(det(t)), we get that it is in Z and it is a unit; so
ε(det(t)) = ±(ε(α) b|G|)
n1
(ε(α) + (n 1)b|G|) = ±1.
We claim that the only integer solutions to these equations are ε(α) = ±1
and b = 0.
Let us first take a look at (ε(α) b|G|)
n1
(ε(α) + (n 1)b|G|) = 1. So,
either (ε(α)b|G|)
n1
= 1 and (ε(α)+(n1)b|G|) = 1, or (ε(α)b|G|)
n1
=
1 and (ε(α) + (n 1)b|G|) = 1. If n is odd, the second option can never
occur, and the only possible integer solutions for the first case are ε(α) = ±1
and b = 0 (since the case n = 1 has already been dealt with and is excluded).
If n is even, we have the desired result immediately.
Analyzing equation (ε(α ) b|G|)
n1
(ε(α) + (n 1)b|G|) = 1, we get
either (ε(α)b|G|)
n1
= 1 and (ε(α )+(n1)b|G|) = 1, or (ε(α)b|G|)
n1
=
1 and (ε(α) + (n 1)b|G|) = 1. If n is odd, the first option is not possible,
and the only existing integer solutions for the second case are ε(α) = ±1 and
b = 0. If n is even, then the only possible integer solutions are the desired
ones (since we have already dealt with the cases n = 2 and G trivial, and
n = 1) .
Because t is a unit and a diagonal matrix with α on all nonzero entries,
we have that α Z(U(ZG)), which finishes the proof.
Theorem 3.1.12. Let S be a finite Brandt semigroup, let G be a maximal
subgroup, and let u U((Z
0
S)
1
). We have that u N(Mon(±G)) if and
only if uu
Z(U((Z
0
S)
1
)).
Proof. We examine separately the case where S = M({1}, 2, 2, I), with I the
2 × 2 identity matrix. We have that (Z
0
S)
1
= M
2
(Z) and Z(U((Z
0
S)
1
)) =
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 51
±I
2
. By means of elementary matrix computations, we see that
N(Mon(±{1})) = {
±1 0
0 ±1
,
0 ±1
±1 0
},
and u N(Mon(±G)) implies uu
= I
2
. Now, if uu
= ±I
2
, for u
U(M
2
(Z)), then, making elementary matrix computations, we get that u =
±1 0
0 ±1
or u =
0 ±1
±1 0
. In either case, u N(Mon(1})).
For the rest of the proof, we assume S = M({1}, 2, 2, I).
Take u U((Z
0
S)
1
) and a Mon(±G). Assume u N(Mon(±G)).
Then b := uau
1
Mon(±G). Hence, applying to both sides, b
= b
1
=
(u
1
)
a
1
u
. Taking inverses in this equality, b = (u
)
1
au
. Thus,
a = u
b(u
)
1
.
So,
u
ua(u
u)
1
= u
uau
1
(u
)
1
= u
b(u
)
1
= u
(u
)
1
au
(u
)
1
= a.
We have proved that u
u commutes with elements from Mon(±G). By
Lemma 3.1.11, it follows that u
u Z(U(Z
0
S)
1
)). So u
u = (u
)
1
u
uu
=
uu
Z(U(Z
0
S)
1
)).
Now, suppose uu
Z(U((Z
0
S)
1
)). Then uu
= u
u and (u
u)
1
=
u
1
(u
1
)
Z(U((Z
0
S)
1
)). We want to show that uau
1
Mon(±G), for
all a Mon(±G). We have that
(uau
1
)(uau
1
)
= ua(u
1
(u
1
)
)a
1
u
= uu
1
(u
1
)
u
= 1.
So, by Theorem 3.1.6, uau
1
Mon(±G), as desired.
By Theorem 3.1.4, (4) we get the following Corollary:
Corollary 3.1.13. Let S be a finite Brandt semigroup and let G be a maximal
subgroup of S. Then N(±S) N(Mon(±G)).
The reverse inclusion remains an open and interesting problem.
When the central units of ZG are trivial, the problem is solved.
Proposition 3.1.14. Let S be a finite Brandt semigroup and let G be a
maximal subgroup of S. We have that N(±S) = Mon(±G) = N(Mon(±G))
if and only if Z(U(ZG)) = ±Z(G).
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 52
Proof. Suppose N(±S) = Mon(±G) = N(Mon(±G)). As Z(U(Z
0
S)
1
))
Scal(Z(U(ZG))) is contained in N(±S) = Mon(±G), we have by Lemma
3.1.7 that Z(U(ZG)) = ±Z(G).
In case Z(U(ZG)) = ±Z(G), then from Theorem 3.1.4, (4) it follows
that for all u N(±S), uu
Scal(±Z(G)); in particular, uu
has finite
order. Thus, from Corollary 3.1.8, u Mon(±G). The other inclusion is
always true. Take u = (u
i,j
) N(Mon(±G)) with u
i,j
=
gG
u
i,j
(g)g
ZG. We have, by Theorem 3.1.12, that uu
= (c
i,j
) Z(U((Z
0
S)
1
)) =
Scal(±Z(G)). For each i, c
i,i
=
j
u
i,j
u
i,j
is a trivial unit with c
i,i
(1) =
j
(
gG
u
i,j
(g)
2
) = 0. It follows that, for each i, c
i,i
= 1, i.e., uu
= 1, and
thus u Mon(±G) by Theorem 3.1.6. The other inclusion is obvious.
Next, we prove a result for the double normalizer in semigroup rings, that
was shown for group rings by Li in [18].
Theorem 3.1.15. Let G be a finite group. Then N(N(Mon(±G))) =
N(Mon(±G)).
Proof. Take v N(N(Mon(±G)) and a Mon(±G). Clearly, Mon(±G)
N(Mon(±G)). So, from Theorem 3.1.12, v
1
av(v
1
av)
Z(U(Z
0
S)
1
))
Scal(Z(U(ZG))). Since u := v
1
av and u
= (v
1
av)
are commuting torsion
units, their product is also a torsion unit. Thus, by Lemma 3.1.7 we have
that c := uu
Scal(±Z(G)).
Now let u = (u
i,j
), with u
i,j
=
gG
u
i,j
(g)g ZG. For each i, c
i,i
=
j
u
i,j
u
i,j
is a trivial unit, with c
i,i
(1) =
j
(
gG
u
i,j
(g)
2
) = 0. So, it
follows that, for each i, c
i,i
= 1, i.e., uu
= 1. Thus a(vv
) = (vv
)a, for
a
= a
1
. From Lemma 3.1.11, this means that vv
Z(U(Z
0
S))). Hence,
v N(Mon(±G)), as desired.
The other inclusion is obvious.
Remark 3.1.16. The definitions of the hypercenter Z
(G) and the finite
conjugacy center Φ(G) of a group G are stated in Definition 1.1.31.
The hypercenter and the finite conjugacy center of the unit group of an
integral group ring and of an integral semigroup ring have been given special
attention in recent years.
It is a well known result that, if G is a finite group, then Z
(U
1
(ZG)) =
Z
2
(U
1
(ZG)) (see [1]) and that Z
(U
1
(ZG)) N
U
1
(ZG)
(G) (see [20] and [19]),
where U
1
(ZG) stands for the normalized units of ZG, i.e., the units in ZG
having augmentation 1.
In Corollary 5.2 and 5.3 in [8], a description is given for the finite conju-
gacy center Φ(U((Z
0
S)
1
)) and second center Z
2
(U((Z
0
S)
1
)) of the unit group
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.1. The Normalizer of a Semigroup 53
of an integral semigroup ring of a finite semigroup S such that QS is semisim-
ple. The result shows that both groups equal the hypercenter Z
(U((Z
0
S)
1
))
and are central if and only if S has no principal factors which are so called
Q
-groups. A torsion group G is said to be a Q
-group if G has an abelian
normal subgroup A of index 2 which has an element a of order 4 such that,
for all h A and all g G \ A, g
2
= a
2
and g
1
hg = h
1
; or, equiva-
lently, U(ZG) contains an abelian periodic normal subgroup H G such
that H ⊆ Z(G) (see [2], [3]).
From the description of N(±S) we gave, it follows that the finite conju-
gacy center Φ(U((Z
0
S)
1
)) and the second center Z
2
(U((Z
0
S)
1
)) (hypercenter)
are always contained in N(±S), similarly to the group ring case, i.e.,
Z
2
(U((Z
0
S)
1
)) = Z
(U((Z
0
S)
1
)) = Φ(U((Z
0
S)
1
)) N(±S).
3.1.2 The Normalizer Problem for Semigroup Rings
The normalizer problem for group rings [36, Problem 43] asks whether
N
U(ZG)
(±G) = Z(U(ZG))(±G),
where G is a group. It has a positive answer for many classes of finite groups,
among which finite nilpotent groups [36, Corollary 9.2]. One can now state
this problem in the setting of semigroup rings: is it true that
N(±S) = Z(U((Z
0
S)
1
))Mon(±G)?
In the case of a Malcev nilpotent semigroup S such that QS is semisimple
we have a positive answer to the analogous problem in semigroup rings.
The only Malcev nilpotent completely 0-simple semigroups are the Brandt
semigroups over a nilpotent group ([16, Lemma 2.1]). As observed before,
we can assume that the principal series of S has only one Rees factor.
Theorem 3.1.17. Let S be a finite Brandt semigroup over a finite nilpotent
group G and let M denote the union of all maximal subgroups of S. Then
N(±M
0
) = Mon(Z(U(ZG))(±G)) and N(±S) = Z(U(Z
0
S)
1
)Mon(±G).
Proof. From Theorem 3.1.4, (2), N(±M
0
) = Mon(N
U(ZG)
(±G)). Because S
is Malcev nilpotent, we have that G is a finite nilpotent group (see Example
1.2.21). Thus, the normalizer problem for ZG has a positive answer and
N
U(ZG)
(±G) = Z(U(ZG))(±G). So,
N(±M
0
) = Mon(N
U(ZG)
(±G)) = Mon(Z(U(ZG))(±G)).
Following the same lines, we get the result for N(±S).
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.2. Free Groups generated by Bicyclic Units 54
In general, the normalizer problem does not hold for group rings, though
the normalizer is known up to finite index [36, Proposition 9.5]. We get the
same result in semigroup rings.
Proposition 3.1.18. Let S be a finite Brandt semigroup, let M denote the
union of all maximal subgroups of S, and let G be a maximal subgroup of S.
If u N(±M
0
), then u
2
Diag(Z(U(ZG)))Mon(±G), and if u N(±S),
then u
2
Z(U(Z
0
S)
1
))Mon(±G).
Proof. Take u N(±M
0
). Define v := u
u
1
, then vv
= u
u
1
(u
1
)
u =
u
(u
u)
1
u. From Corollary 3.1.5, we have vv
= u
(uu
)
1
u = 1. Hence by
Theorem 3.1.6 we have that v Mon(±G). So, u
= vu and uu
= u
u =
vu
2
Diag(Z(U(ZG))) by Theorem 3.1.4, (3).
The same reasoning gives the result for u N(±S).
Corollary 3.1.19. Let S be a finite Brandt semigroup and G a maximal
subgroup of S. Then
N(±S)
Z((U(Z
0
S)
1
))Mon(±G)
is an elementary abelian 2-group.
3.2 Free Groups generated by Bicyclic Units
By Hartley and Pickel [11], we know that there are free groups contained
in the unit group of an integral semigroup ring. Marciniak and Sehgal [23]
constructed a free group of rank 2 in the unit group of an integral group ring
using a nontrivial bicyclic unit (Definition 1.1.28) and its image under the
classical involution (Definition 1.1.3).
Since a Brandt semigroup S has the involution (see Section 3.1 and Def-
inition 1.2.11), we can investigate the same problem for a nontrivial bicyclic
unit of (Z
0
S)
1
.
Theorem 3.2.1. Let S be a Brandt semigroup. Take s S such that the
cyclic semigroup s is a group of order n, and t S such that u
s,t
= 1 +
(1 s)ts is a nontrivial bicyclic unit in (Z
0
S)
1
. Then:
1. if st is in a maximal subgroup G of S and if s is not normal in t,
then u
s,t
, (u
s,t
)
is a free subgroup of U((Z
0
S)
1
);
2. if st = 0 and o(s) 2, then u
s,t
, (u
s,t
)
is a free subgroup of
U((Z
0
S)
1
);
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.3. Some Questions for Further Investigation 55
3. if st = 0 and o(s) = 1, then u
s,t
, (u
s,t
)
is not a f ree subgroup of
U((Z
0
S)
1
).
Proof. Recall that, being a Brandt semigroup, we have that (see Theorem
1.2.14) S M
0
(G, n, n, I
n
) and M
0
{s = ge
i,i
M
0
(G, n, n, I
n
); g
G, i = 1, . . . , n}, where I
n
is the n × n identity matrix and e
i,j
are matrix
units (Example 1.2.2.1).
Since s generates a subgroup of order n in S, it is of the form s = ge
i,i
,
for g G, i = 1, . . . , n. Notice that in order for u
s,t
to be nontrivial we must
have t = he
j,i
, for h G, j = 1, . . . , n.
1. If st is in a maximal subgroup G of S, then we must have j = i. So
u
s,t
= u
g,h
e
i,i
and, since s is not normal in t (i.e., h ∈ N
G
(g), u
s,t
is a
nontrivial bicyclic unit in (Z
0
S)
1
and u
g,h
is a nontrivial bicyclic unit in ZG.
So (u
s,t
)
= u
g,h
e
i,i
. Thus, Marciniak and Sehgal’s main result in [23] gives
us that u
s,t
, (u
s,t
)
is a free subgroup of U((Z
0
S)
1
).
2. If st = 0, this means that j = i. Then u
s,t
= 1 + hge
j,i
and (u
s,t
)
=
1 + gh
1
e
i,j
.
When o(g) 2, consider the ring homomorphism
φ : (Z
0
S)
1
M
n
(Z) given by α = (α
i,j
) (Z
0
S)
1
→ (ε(α
i,j
)) M
n
(Z),
where ε is the augmentation mapping in ZG. By Sanov’s Theorem ([25, The-
orem 10.1.3]) applied to the 2 × 2 nonzero submatrix of φ(u
s,t
) and φ(u
s,t
)
),
we obtain the result.
3. Since st = 0, we have that j = i and u
s,t
= 1+hge
j,i
, (u
s,t
)
= 1+gh
1
e
i,j
.
When g = 1, then u
s,t
= 1+he
j,i
, (u
s,t
)
= 1+h
1
e
i,j
and ((u
s,t
)
)
1
= 1
h
1
e
i,j
. Thus, by pe rforming elementary matrix computations, u
s,t
((u
s,t
)
)
1
is of order 6. Hence, u
s,t
, (u
s,t
)
is not a free group.
3.3 Some Questions for Further
Investigation
So far, in this chapter, we have always considered semigroups for which
the rational semigroup algebra is semisimple. It remains open what N(±S) is
in case there is a Jacobson radical (see Definition 1.1.4 and Theorem 1.1.10).
The following example indicates that N(±S) might always be central.
Example 3.3.1. Let G be a finite group. Define S := {Ge
1,2
, Ge
1,3
, G
2,3
},
where e
i,j
are 3 × 3 matrix units (Example 1.2.2.1). Then T := (S
0
)
1
is a
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
3.3. Some Questions for Further Investigation 56
finite semigroup with zero element and identity and
Γ := (Z
0
T )
1
= Z
0
T =
z ZG ZG
0 z ZG
0 0 z
; z Z
is an integral semigroup ring, having Jacobson radical J (Γ) = ZGe
1,2
+
ZGe
1,3
+ ZGe
2,3
. Observe that U(Γ) = 1 + J (Γ).
Let us now compute N(±T ). Take u = ±(
3
i=1
e
i,i
) + te
1,2
+ ve
1,3
+ xe
2,3
,
where t, v, x ZG. In order to normalize ge
1,2
, with g ±G, it follows that
x = 0. Note that u already normalizes ge
1,3
, and that ge
2,3
is normalized by
u if and only if t = 0.
Hence,
N(±T ) = (
3
i=1
e
i,i
) + ve
1,3
; v ZG} = Z(U(Γ)).
As it has been said in the beginning of this chapter, the study of the
normalizer for semigroup rings, in analogy to what happens in group rings,
might be e lucidative in tackling the isomorphism problem. However, this
connection still has to be made in the context of semigroup rings, and this
is a natural direction for further studies on the subject.
It should also be interesting to investigate the usefulness of the results
obtained to the isomorphism problem for partial group rings, for which it may
be necessary to further explore the structure of the semigroup S
G
associated
to a given group G.
The Normalizer of a Finite Semigroup and Free Groups in the Unit Group
of an Integral Semigroup Ring
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Abelian Group Algebras and of Complex Nilpotent Algebras, Proceed-
ings of the Edinburgh Mathematical Society (submitted)
[34] D. J. S. Robinson, A Course in the Theory of Groups, Springer-Verlag,
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Bibliography
Index
I × M matrix over G
0
, 15
Rees matrix, 15
zero matrix, 15
regular matrix, 18
augmentation ideal, 1
R
(G, N), 1
augmentation mapping, 1
ε
N
, 1
character table, 7, 12, 25
code, 31
cyclic, 31
cyclic shift, 31
dimension, 31
length, 31
field
perfect, 3
splitting, 8
group, 14
n
th
center, 9
Q
-group, 53
abelian, 14
central height, 9
centralizer, 9
commutative, 14
commutator, 9
FC center, 9
hypercenter, 9
subgroup, 16
upper central series, 9
with zero, 15
group algebra, 1
H, 32
abelian group
central idempotents, 25, 28,
29
polynomial P
l
, 26
complex field
central idempotents, 25, 36
Isomorphism Problem, 26, 38,
40
nilpotent group
central idempotents, 25, 36
primitive central idempotent
G
e
, 31
ε(G), 31
group character, 6
irreducible, 6
regular, 6
group representation, 5
degree, 5
equivalent, 5
irreducible, 5
matrix representation, 5
regular, 6
group ring, 1
H, 4
a, 4
H, 4, 5
We dderburn–Artin decomposi-
tion, 7, 10
bicyclic unit, 8
class sums, 4
coefficient of g in α, 1
involution, 2
60
61
classical, 2
Isomorphism Problem, 26, 38,
40
normalized unit, 52
primitive central idempotent
G
e
, 31
primitive central idempotents,
25
product of elements, 1
sum of elements, 1
support of an element, 1
trivial unit, 8
unitary unit, 9
We dderburn–Artin decomposi-
tion, 25, 26
Maschke Theorem, 4
matrix unit, 16, 22
module
completely reducible, 3
direct summand, 3
irreducible, 2
semisimple, 3
simple, 2
monoid, 14
invertible element, 14
inverse element, 14
submonoid, 16
unit, 14
inverse element, 14
unit group, 14
monomial algebra, 23
Munn ring, 22
Perlis–Walker Theorem, 10
Rees matrix semigroup, 15
idempotents, 18
multiplication, 15
ring
idempotent, 2
nontrivial, 2
orthogonal, 2
primitive, 2
involution, 2
primitive central idempotents,
4, 12
simpe, 2
simple components, 4
ring of matrix type, 22
addition, 22
multiplication, 22
sandwich matrix, 22
semigroup, 14
0-simple, 19
completely 0-simple, 19
adjoining a zero, 15
adjoining an identity, 15
Brandt, 19
center, 17
congruence relation, 18
left, 18
Rees congruence, 18
right, 18
cyclic, 16
factor semigroup, 18
Rees factor semigroup, 18
homomorphism, 14
ideal, 17
generated by an element, 17
left, 17
right, 17
idempotent, 16
primitive, 16
identity, 14
inverse, 17
kernel, 17
Malcev nilpotent, 21
maximal subgroup, 17
null, 14
periodic, 16
periodic element, 16
Index
62
principal factor, 20
principal series, 20
factors, 20
regular, 17
Von Neumann condition, 17
relation J , 20
I
x
, 20
J(x), 20
J -class, 20
J -equivalence, 20
simple, 19
subsemigroup, 16
zero element, 14
semigroup algebra, 21
Isomorphism Problem, 40
semigroup ring, 21
coefficient of s in α, 21
contracted, 22
Isomorphism Problem, 40
product of elements, 21
sum of elements, 21
support of an element, 21
We dderburn–Artin Theorem, 4
We dderburn–Malcev Theorem, 3
Index
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